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onegirl
Group Title
Draw the second derivative given the graph of function f below.
 one year ago
 one year ago
onegirl Group Title
Draw the second derivative given the graph of function f below.
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
first derivative of a parabola is probably a line second derivative will therefore be a constant, aka a horizontal line
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay can u show it?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
dw:1362594670556:dw how will i draw it on here?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix can u help?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595003756:dwLet's draw some tangent lines to get a feel for what is going on
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595106001:dwSee how the SLOPE of the porabola is very negative on the left? The line is pointing downward, very negative. That line has a bad attitude! XD That is telling us that the VALUE of our first derivative will be very negative. I've drawn a point near the bottom to show this.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595210278:dwCheck out this tangent line. It's still pointing downward, but not as much as the last one. It has a less negative slope. So our first derivative will have a negative value, but not as negative as the first point.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595320296:dwHow about this tangent line, what is it's value?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
what is the slope of this tangent line i mean*
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595394811:dwyes good. so the VALUE of our derivative will be 0.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595424698:dwWhen we go towards the right, the slope becomes positive. So our point will be somewhere up in the positive area.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595476831:dwAs we go further to the right, our slope gets really positive, so the value of the first derivative will be very positive.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Ok let's draw a line connecting these points.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595554967:dwI had to fix a couple of the dots :) lol
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay that makes sense now
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
So how about the second derivative. Hmmm
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
it will be horizontal
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362595623497:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yes good! Because the slope of this line is constant yes? If we were to check points, we would see that the tangent lines are all giving us the same slope.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
With the way I've drawn this particular first derivative, it has a slope of approximately 1. So our second derivative would have a VALUE of 1.dw:1362595735329:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Just make sure that you draw your second derivative ABOVE the xaxis. That shows that the first derivative was positive.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay thanks
 one year ago
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