Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Draw the second derivative given the graph of function f below.

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

1 Attachment
first derivative of a parabola is probably a line second derivative will therefore be a constant, aka a horizontal line
okay can u show it?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1362594670556:dw| how will i draw it on here?
@zepdrix can u help?
|dw:1362595003756:dw|Let's draw some tangent lines to get a feel for what is going on
|dw:1362595106001:dw|See how the SLOPE of the porabola is very negative on the left? The line is pointing downward, very negative. That line has a bad attitude! XD That is telling us that the VALUE of our first derivative will be very negative. I've drawn a point near the bottom to show this.
|dw:1362595210278:dw|Check out this tangent line. It's still pointing downward, but not as much as the last one. It has a less negative slope. So our first derivative will have a negative value, but not as negative as the first point.
|dw:1362595320296:dw|How about this tangent line, what is it's value?
what is the slope of this tangent line i mean*
|dw:1362595394811:dw|yes good. so the VALUE of our derivative will be 0.
|dw:1362595424698:dw|When we go towards the right, the slope becomes positive. So our point will be somewhere up in the positive area.
|dw:1362595476831:dw|As we go further to the right, our slope gets really positive, so the value of the first derivative will be very positive.
Ok let's draw a line connecting these points.
|dw:1362595554967:dw|I had to fix a couple of the dots :) lol
okay that makes sense now
So how about the second derivative. Hmmm
it will be horizontal
Yes good! Because the slope of this line is constant yes? If we were to check points, we would see that the tangent lines are all giving us the same slope.
With the way I've drawn this particular first derivative, it has a slope of approximately 1. So our second derivative would have a VALUE of 1.|dw:1362595735329:dw|
Just make sure that you draw your second derivative ABOVE the x-axis. That shows that the first derivative was positive.
okay thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question