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x4/x+2<1 because the x4 is divided by x+2 well times both sides by x+2 so we now have the following (x+2) (x4)<1(x+2) than we distr (x+2) (x4) which we get x^23<1 did i miss something here plz help
 one year ago
 one year ago
x4/x+2<1 because the x4 is divided by x+2 well times both sides by x+2 so we now have the following (x+2) (x4)<1(x+2) than we distr (x+2) (x4) which we get x^23<1 did i miss something here plz help
 one year ago
 one year ago

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godorovgBest ResponseYou've already chosen the best response.0
am I on the right track?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
you would normally multiply by the square of the denominator \[(x + 2)(x 4) < (x + 2)^2\] because if you multiply by (x + 2) you have \[\frac{(x  4)}{(x + 2)} \times (x + 2) < 1 \times (x + 2)\] which becomes \[\frac{(x 4)(x+2)}{(x +2)} < (x +2) \] cancel the common factor in the fraction leaves \[(x 4) < (x + 2)\] hope this helps
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
well 1 times anything is 1 so 1 times (x + 2) is x + 2
 one year ago
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