## anonymous 3 years ago how o u solve (3x^2y)^3

1. Mertsj

$(3x^2y)^3=3^3(x^2)^3(y^1)^3$

2. Mertsj

Does that help?

3. Mertsj

What is 3 to the third?

4. campbell_st

the power of 3 is operating on each part of the expression and can be written in expanded form as $3^3 \times (x^2)^3 \times (y^1)^3$ to simplify the variables use the index law for power of a power which means multiply the powers $(x^a)^b = x^{a \times b}$

5. anonymous

thank u guys