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SWAG

  • 3 years ago

how o u solve (3x^2y)^3

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  1. Mertsj
    • 3 years ago
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    \[(3x^2y)^3=3^3(x^2)^3(y^1)^3\]

  2. Mertsj
    • 3 years ago
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    Does that help?

  3. Mertsj
    • 3 years ago
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    What is 3 to the third?

  4. campbell_st
    • 3 years ago
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    the power of 3 is operating on each part of the expression and can be written in expanded form as \[3^3 \times (x^2)^3 \times (y^1)^3\] to simplify the variables use the index law for power of a power which means multiply the powers \[(x^a)^b = x^{a \times b}\]

  5. SWAG
    • 3 years ago
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    thank u guys

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