## onegirl 2 years ago If y = 3^x(lnx^2) , find dy/dx.

1. juanjohnguy

Did you just need help calculating it?

2. onegirl

yea

3. Twis7ed

Is the equation? $3^{x}*\ln(x^2)$

4. onegirl

yes

5. juanjohnguy

We would need to apply both the prodcut rule and chain rule

6. onegirl

ok

7. juanjohnguy

We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

8. juanjohnguy

there is a quick little formula for finding the derivative of a constant to the x power

9. onegirl

okay

10. juanjohnguy

If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

11. onegirl

ok

12. juanjohnguy

so go ahead and trying doing it

13. onegirl

okay i'll try thanks

14. juanjohnguy

np

15. onegirl

i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

16. juanjohnguy

let me quickly calculate it

17. onegirl

ok

18. juanjohnguy

$3^x*3\ln(x^2)+(2x/x^2)*3^x$

19. juanjohnguy

Thats what I got and I'm pretty sure it is right

20. onegirl

okay

21. juanjohnguy

Sorry I need to go but good luck