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onegirl

  • 2 years ago

If y = 3^x(lnx^2) , find dy/dx.

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  1. juanjohnguy
    • 2 years ago
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    Did you just need help calculating it?

  2. onegirl
    • 2 years ago
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    yea

  3. Twis7ed
    • 2 years ago
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    Is the equation? \[3^{x}*\ln(x^2)\]

  4. onegirl
    • 2 years ago
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    yes

  5. juanjohnguy
    • 2 years ago
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    We would need to apply both the prodcut rule and chain rule

  6. onegirl
    • 2 years ago
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    ok

  7. juanjohnguy
    • 2 years ago
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    We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

  8. juanjohnguy
    • 2 years ago
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    there is a quick little formula for finding the derivative of a constant to the x power

  9. onegirl
    • 2 years ago
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    okay

  10. juanjohnguy
    • 2 years ago
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    If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

  11. onegirl
    • 2 years ago
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    ok

  12. juanjohnguy
    • 2 years ago
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    so go ahead and trying doing it

  13. onegirl
    • 2 years ago
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    okay i'll try thanks

  14. juanjohnguy
    • 2 years ago
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    np

  15. onegirl
    • 2 years ago
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    i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

  16. juanjohnguy
    • 2 years ago
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    let me quickly calculate it

  17. onegirl
    • 2 years ago
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    ok

  18. juanjohnguy
    • 2 years ago
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    \[3^x*3\ln(x^2)+(2x/x^2)*3^x\]

  19. juanjohnguy
    • 2 years ago
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    Thats what I got and I'm pretty sure it is right

  20. onegirl
    • 2 years ago
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    okay

  21. juanjohnguy
    • 2 years ago
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    Sorry I need to go but good luck

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