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If y = 3^x(lnx^2) , find dy/dx.

Mathematics
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Did you just need help calculating it?
yea
Is the equation? \[3^{x}*\ln(x^2)\]

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Other answers:

yes
We would need to apply both the prodcut rule and chain rule
ok
We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)
there is a quick little formula for finding the derivative of a constant to the x power
okay
If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna
ok
so go ahead and trying doing it
okay i'll try thanks
np
i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)
let me quickly calculate it
ok
\[3^x*3\ln(x^2)+(2x/x^2)*3^x\]
Thats what I got and I'm pretty sure it is right
okay
Sorry I need to go but good luck

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