onegirl
If y = 3^x(lnx^2) , find dy/dx.
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juanjohnguy
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Did you just need help calculating it?
onegirl
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yea
Twis7ed
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Is the equation? \[3^{x}*\ln(x^2)\]
onegirl
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yes
juanjohnguy
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We would need to apply both the prodcut rule and chain rule
onegirl
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ok
juanjohnguy
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We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)
juanjohnguy
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there is a quick little formula for finding the derivative of a constant to the x power
onegirl
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okay
juanjohnguy
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If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna
onegirl
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ok
juanjohnguy
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so go ahead and trying doing it
onegirl
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okay i'll try thanks
juanjohnguy
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np
onegirl
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i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)
juanjohnguy
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let me quickly calculate it
onegirl
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ok
juanjohnguy
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\[3^x*3\ln(x^2)+(2x/x^2)*3^x\]
juanjohnguy
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Thats what I got and I'm pretty sure it is right
onegirl
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okay
juanjohnguy
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Sorry I need to go but good luck