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onegirl Group Title

If y = 3^x(lnx^2) , find dy/dx.

  • one year ago
  • one year ago

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  1. juanjohnguy Group Title
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    Did you just need help calculating it?

    • one year ago
  2. onegirl Group Title
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    yea

    • one year ago
  3. Twis7ed Group Title
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    Is the equation? \[3^{x}*\ln(x^2)\]

    • one year ago
  4. onegirl Group Title
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    yes

    • one year ago
  5. juanjohnguy Group Title
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    We would need to apply both the prodcut rule and chain rule

    • one year ago
  6. onegirl Group Title
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    ok

    • one year ago
  7. juanjohnguy Group Title
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    We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

    • one year ago
  8. juanjohnguy Group Title
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    there is a quick little formula for finding the derivative of a constant to the x power

    • one year ago
  9. onegirl Group Title
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    okay

    • one year ago
  10. juanjohnguy Group Title
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    If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

    • one year ago
  11. onegirl Group Title
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    ok

    • one year ago
  12. juanjohnguy Group Title
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    so go ahead and trying doing it

    • one year ago
  13. onegirl Group Title
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    okay i'll try thanks

    • one year ago
  14. juanjohnguy Group Title
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    np

    • one year ago
  15. onegirl Group Title
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    i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

    • one year ago
  16. juanjohnguy Group Title
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    let me quickly calculate it

    • one year ago
  17. onegirl Group Title
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    ok

    • one year ago
  18. juanjohnguy Group Title
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    \[3^x*3\ln(x^2)+(2x/x^2)*3^x\]

    • one year ago
  19. juanjohnguy Group Title
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    Thats what I got and I'm pretty sure it is right

    • one year ago
  20. onegirl Group Title
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    okay

    • one year ago
  21. juanjohnguy Group Title
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    Sorry I need to go but good luck

    • one year ago
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