anonymous
  • anonymous
If y = 3^x(lnx^2) , find dy/dx.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Did you just need help calculating it?
anonymous
  • anonymous
yea
anonymous
  • anonymous
Is the equation? \[3^{x}*\ln(x^2)\]

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anonymous
  • anonymous
yes
anonymous
  • anonymous
We would need to apply both the prodcut rule and chain rule
anonymous
  • anonymous
ok
anonymous
  • anonymous
We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)
anonymous
  • anonymous
there is a quick little formula for finding the derivative of a constant to the x power
anonymous
  • anonymous
okay
anonymous
  • anonymous
If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna
anonymous
  • anonymous
ok
anonymous
  • anonymous
so go ahead and trying doing it
anonymous
  • anonymous
okay i'll try thanks
anonymous
  • anonymous
np
anonymous
  • anonymous
i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)
anonymous
  • anonymous
let me quickly calculate it
anonymous
  • anonymous
ok
anonymous
  • anonymous
\[3^x*3\ln(x^2)+(2x/x^2)*3^x\]
anonymous
  • anonymous
Thats what I got and I'm pretty sure it is right
anonymous
  • anonymous
okay
anonymous
  • anonymous
Sorry I need to go but good luck

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