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onegirl

  • one year ago

If y = 3^x(lnx^2) , find dy/dx.

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  1. juanjohnguy
    • one year ago
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    Did you just need help calculating it?

  2. onegirl
    • one year ago
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    yea

  3. Twis7ed
    • one year ago
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    Is the equation? \[3^{x}*\ln(x^2)\]

  4. onegirl
    • one year ago
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    yes

  5. juanjohnguy
    • one year ago
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    We would need to apply both the prodcut rule and chain rule

  6. onegirl
    • one year ago
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    ok

  7. juanjohnguy
    • one year ago
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    We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

  8. juanjohnguy
    • one year ago
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    there is a quick little formula for finding the derivative of a constant to the x power

  9. onegirl
    • one year ago
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    okay

  10. juanjohnguy
    • one year ago
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    If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

  11. onegirl
    • one year ago
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    ok

  12. juanjohnguy
    • one year ago
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    so go ahead and trying doing it

  13. onegirl
    • one year ago
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    okay i'll try thanks

  14. juanjohnguy
    • one year ago
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    np

  15. onegirl
    • one year ago
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    i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

  16. juanjohnguy
    • one year ago
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    let me quickly calculate it

  17. onegirl
    • one year ago
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    ok

  18. juanjohnguy
    • one year ago
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    \[3^x*3\ln(x^2)+(2x/x^2)*3^x\]

  19. juanjohnguy
    • one year ago
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    Thats what I got and I'm pretty sure it is right

  20. onegirl
    • one year ago
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    okay

  21. juanjohnguy
    • one year ago
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    Sorry I need to go but good luck

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