## anonymous 3 years ago If y = 3^x(lnx^2) , find dy/dx.

1. anonymous

Did you just need help calculating it?

2. anonymous

yea

3. anonymous

Is the equation? $3^{x}*\ln(x^2)$

4. anonymous

yes

5. anonymous

We would need to apply both the prodcut rule and chain rule

6. anonymous

ok

7. anonymous

We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

8. anonymous

there is a quick little formula for finding the derivative of a constant to the x power

9. anonymous

okay

10. anonymous

If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

11. anonymous

ok

12. anonymous

so go ahead and trying doing it

13. anonymous

okay i'll try thanks

14. anonymous

np

15. anonymous

i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

16. anonymous

let me quickly calculate it

17. anonymous

ok

18. anonymous

$3^x*3\ln(x^2)+(2x/x^2)*3^x$

19. anonymous

Thats what I got and I'm pretty sure it is right

20. anonymous

okay

21. anonymous

Sorry I need to go but good luck