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anonymous
 3 years ago
If y = 3^x(lnx^2) , find dy/dx.
anonymous
 3 years ago
If y = 3^x(lnx^2) , find dy/dx.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Did you just need help calculating it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is the equation? \[3^{x}*\ln(x^2)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We would need to apply both the prodcut rule and chain rule

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there is a quick little formula for finding the derivative of a constant to the x power

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so go ahead and trying doing it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got dy/dx = 2(3^x)/x  3^x(ln3)(lnx^2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me quickly calculate it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[3^x*3\ln(x^2)+(2x/x^2)*3^x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thats what I got and I'm pretty sure it is right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry I need to go but good luck
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