WHERE IS MY MISTAKE?!?!?
Problem: Given that sinƟ = 2/3 and Π/2 < Ɵ < Π find the exact value of cosƟ
My solution:
cos^2(Ɵ) + sin^2(Ɵ) = 1
sin^2(Ɵ) = 1 - cos^2(Ɵ)
4/9=1- cos^2(Ɵ)
-5/9 = -cos^2(Ɵ)
5/9 = cos^2(Ɵ)
cos(Ɵ) = -sqrt(5/9)
Where is my mistake till now?

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for one thing, the square root of 9 is 3

other than that, it is all correct

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