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for one thing, the square root of 9 is 3

other than that, it is all correct

@satellite73 So I didnt make any mistakes at all?

No.

just draw a triangle and with 0 = 2 and h = 3.. then find a then do a/h to get cos theta

|dw:1362625931832:dw|

I should have used another fundamental identity?

got it its the same just modified, meeh

it is right, everything you did is right

I know
why its negative yea

problem is that My solution is different from the one on the book

what did the book get?

They the solutions might be equal but, I sill found a different solution

5/9

a different solution, or a different method

yea right..

nothing wrong with your method
answer is \(-\frac{\sqrt{5}}{3}\) for sure

Books solution: 5/9

no that is \(\cos^2(\theta)\)

what do you mean "no that is cos2(θ)" ?

\[\cos(\theta)=-\frac{\sqrt{5}}{3}\]
\[\cos^2(\theta)=\frac{5}{9}\]

hmmmmm

I AM SORRY the answer in my book was: -sqrt(5)/3 !!!!!

|dw:1362626751880:dw|

So my final outcome is - sqrt(5)/sqrt3 HOW DO I PROCEED?

SOLVED THANK YOU ALL, SPECIAL THANKS TO SATELITE