anonymous
  • anonymous
f(x)=[Inx]^4
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
geerky42
  • geerky42
Do you know chain rule? @Dodo1
anonymous
  • anonymous
Logarithmic Derivative rules that i have to use
anonymous
  • anonymous
Yes I do, f'(g(x).g(x)'

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

geerky42
  • geerky42
Yeah. Use it. You should get 4(lnx)³ · (1/x)
anonymous
  • anonymous
is that answer?
anonymous
  • anonymous
its not Logarithmic Derivative is it?
anonymous
  • anonymous
@zepdrix any ideas?
zepdrix
  • zepdrix
Why would they want you to apply Logarithmic Differentiation to this problem? Very strange... Ok I guess we can do it though :\ Rewrite \(\large f(x)\) as \(\large y\). Then take the log (base e) of both sides. \[\large \ln y=\ln\left[(\ln x)^4\right]\]
anonymous
  • anonymous
put In to both side, ok
zepdrix
  • zepdrix
Using a rule of logarithms,\[\large \color{royalblue}{\log(b^\color{orangered}{a})=\color{orangered}{a}\log(b)}\] We can bring that 4 out front.
zepdrix
  • zepdrix
This is going to be a much more difficult problem using Logarithmic Differentiation. I'm not sure why the directions would suggest you do this :) lol
zepdrix
  • zepdrix
\[\large \ln y=4 \ln\left[\ln x\right]\]
zepdrix
  • zepdrix
Take the derivative of both sides with respect to x. Wanna take a shot at that part? :) What do you get on the left side of the equation?
anonymous
  • anonymous
4log(x)?
zepdrix
  • zepdrix
whut? D:
geerky42
  • geerky42
What do you get on the left side of the equation? LEFT side
anonymous
  • anonymous
oh left x/1?
anonymous
  • anonymous
No its just Y?
anonymous
  • anonymous
Im really bad at log stff!
anonymous
  • anonymous
@geerky42 ?
anonymous
  • anonymous
Oh! I see ops
zepdrix
  • zepdrix
y'/y
anonymous
  • anonymous
1/y' is y'/y?
zepdrix
  • zepdrix
\[\large \frac{d}{dx}\ln y \qquad = \qquad \frac{1}{y}\cdot\frac{dy}{dx}\]
anonymous
  • anonymous
thats cool!
anonymous
  • anonymous
so 1/y*dy/x= In[Inx]^4. do i use chain rule for the next step?

Looking for something else?

Not the answer you are looking for? Search for more explanations.