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geerky42Best ResponseYou've already chosen the best response.1
Do you know chain rule? @Dodo1
 one year ago

Dodo1Best ResponseYou've already chosen the best response.0
Logarithmic Derivative rules that i have to use
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
Yeah. Use it. You should get 4(lnx)³ · (1/x)
 one year ago

Dodo1Best ResponseYou've already chosen the best response.0
its not Logarithmic Derivative is it?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
Why would they want you to apply Logarithmic Differentiation to this problem? Very strange... Ok I guess we can do it though :\ Rewrite \(\large f(x)\) as \(\large y\). Then take the log (base e) of both sides. \[\large \ln y=\ln\left[(\ln x)^4\right]\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
Using a rule of logarithms,\[\large \color{royalblue}{\log(b^\color{orangered}{a})=\color{orangered}{a}\log(b)}\] We can bring that 4 out front.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
This is going to be a much more difficult problem using Logarithmic Differentiation. I'm not sure why the directions would suggest you do this :) lol
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
\[\large \ln y=4 \ln\left[\ln x\right]\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
Take the derivative of both sides with respect to x. Wanna take a shot at that part? :) What do you get on the left side of the equation?
 one year ago

geerky42Best ResponseYou've already chosen the best response.1
What do you get on the left side of the equation? LEFT side
 one year ago

Dodo1Best ResponseYou've already chosen the best response.0
Im really bad at log stff!
 one year ago

zepdrixBest ResponseYou've already chosen the best response.2
\[\large \frac{d}{dx}\ln y \qquad = \qquad \frac{1}{y}\cdot\frac{dy}{dx}\]
 one year ago

Dodo1Best ResponseYou've already chosen the best response.0
so 1/y*dy/x= In[Inx]^4. do i use chain rule for the next step?
 one year ago
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