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geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Do you know chain rule? @Dodo1

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0Logarithmic Derivative rules that i have to use

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Yeah. Use it. You should get 4(lnx)³ · (1/x)

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0its not Logarithmic Derivative is it?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Why would they want you to apply Logarithmic Differentiation to this problem? Very strange... Ok I guess we can do it though :\ Rewrite \(\large f(x)\) as \(\large y\). Then take the log (base e) of both sides. \[\large \ln y=\ln\left[(\ln x)^4\right]\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Using a rule of logarithms,\[\large \color{royalblue}{\log(b^\color{orangered}{a})=\color{orangered}{a}\log(b)}\] We can bring that 4 out front.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2This is going to be a much more difficult problem using Logarithmic Differentiation. I'm not sure why the directions would suggest you do this :) lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \ln y=4 \ln\left[\ln x\right]\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Take the derivative of both sides with respect to x. Wanna take a shot at that part? :) What do you get on the left side of the equation?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1What do you get on the left side of the equation? LEFT side

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0Im really bad at log stff!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \frac{d}{dx}\ln y \qquad = \qquad \frac{1}{y}\cdot\frac{dy}{dx}\]

Dodo1
 one year ago
Best ResponseYou've already chosen the best response.0so 1/y*dy/x= In[Inx]^4. do i use chain rule for the next step?
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