theslytherinhelper
  • theslytherinhelper
Please help. Algebra 2.
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
lol :) whats your question??
theslytherinhelper
  • theslytherinhelper
\[4x ^{2} - 32x + 48 / 3x ^{2} - 17x -6\]
theslytherinhelper
  • theslytherinhelper
lol no, not 911 xD unless that's a user. I just figured out how to work this, bear with me guys

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dmezzullo
  • dmezzullo
Lol, i am sorry, Well if u have anymore questions about this site message me or ask me if u see me in a chat.
anonymous
  • anonymous
lol I got you....... I got you......give me a second to come up with an answer!!
theslytherinhelper
  • theslytherinhelper
So, I mean, what I have so far is the simplified(?) version of the top equation. 4(x^2 - 8x + 12) --> 4(x-2)(x-6) @dmezzullo I'll be sure to! @space4cadet101 Thank you!
theslytherinhelper
  • theslytherinhelper
*top part of the equation
amistre64
  • amistre64
you have a rational expression. It has many properties that can be obtained from it. But without knowing what you are having to do with it, its pretty nominal at best.
phi
  • phi
you can try factoring the bottom using this as a first guess (3x )(x ) the numbers after the x terms have to be factors of 6: either 1 and 6 or 2 and 3 (with different signs)
theslytherinhelper
  • theslytherinhelper
I'm sorry guys, I totally just went through the lesson a millionth time, did the equation with the instruction video, and I get it now. Thanks for all your help, though!
amistre64
  • amistre64
as long as you get it now, its all good ;)

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