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space4cadet101
Group Title
I have a Geometry question if anybody can help!! :) thnx!!!
 one year ago
 one year ago
space4cadet101 Group Title
I have a Geometry question if anybody can help!! :) thnx!!!
 one year ago
 one year ago

This Question is Closed

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
welcome!!!
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
In triangle DEF, what is the length of DF?
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
here is the question.....i am not really sure how to do it??
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Well, for starters, DF is the hypotenuse of this right triangle, right? :)
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
yes!!
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Yes... let's redraw this figure, but only including the relevant stuff... dw:1362665968423:dw Now, with respect to the sixty degree angle, what is the side measuring 45?
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
I am not really sure I would think the other angle down below would be 30 degrees if there was one?? I would guess it would be 30 square root of three??
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Hang on :) Is this side... dw:1362666135050:dw Opposite to the 60 degree angle? Is it adjacent to it?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Oh wait, it seems like you already got the answer down...
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
wait what??
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Okay, forget what I said. Do you use sines and cosines already? :D
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
yes I did but can you give me the math part of the equation like how to do it?? I mean I think I know how to do it but I need someone to just write out how they did the equation! if that makes any since??
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Okay, you want to use sines and cosines, or just the properties of the socalled 306090 triangles?
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
YES!!!
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Yes, what? I gave you a choice :P
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
oo sorry I only looked at the last one which is 306090 traingles that is what i wanted
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
LOL OK :) so... suppose we have a 306090 triangle dw:1362666525444:dw
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
okay :)
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Now, if one side measures...dw:1362666670884:dw This is the side opposite the 30degree angle, right?
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
yes!
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Well, in this case..., the angle opposite the 60degree angle would measure... dw:1362666746027:dw And the hypotenuse would measure
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
dw:1362666784331:dw
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
umm....well I guess 45??
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
What? I didn't ask you anything yet... :P But yeah, you're given the side opposite the 60 degree angle, so that's 45. And this is equal to x sqrt(3) So... \[\large 45=x\sqrt3\] Now solve for x. Actually, solve for 2x, since that's the measure of the hypontenuse.
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
*hypotenuse
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
wait this is were I get confused is adding them up!!
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
Okay, slowly... \[45=x\sqrt3\]Now multiply both sides by 2 \[90=2x\sqrt3\]Now divide both sides by sqrt(3) \[\large \frac{90}{\sqrt{3}}=2x\]And rationalise the denominator... \[\large \frac{90\sqrt{3}}{3}=2x\]\[\huge 30\sqrt3=2x\]And so you were right the first time :D
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
okay wow that is really nice of you to write all of that out for me :) thank you so much!! I will give you a medal for all of your help!! thank you :) have a great day!!
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
No problem :)
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.2
But make sure you got how to do this... it's really a rewarding feeling, solving one type of problem for the first time on your own... real satisfying :)
 one year ago

space4cadet101 Group TitleBest ResponseYou've already chosen the best response.1
yeah!! I will write down those steps you gave me and use them in the future!! thank you :)
 one year ago
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