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How far apart are the foci of an ellipse with a major axis of 26 feet and a minor axis of 24 feet?

Mathematics
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a^2+b^2=c^2
do i just put the numbers into the equation? :/ these are the answer choices:4 feet 5 feet 10 feet 20 feet
If the major axis is 26, then 2a is 26 and a is 13. If the minor axis is 24, then 2b is 24 and b is 12. Use the values of a and b to calculate c

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Other answers:

do you know the Pythagorean triples or no
hmm no i don't
what do you mean 2a? a? 2b?
The distance between the focal points is 2a=26 and 2b=24
so plug here a^2+b^2=c^2
The length of the major axis is 2a and that of the minor axis is 2b like @begzat said. Find the eccentricity of the ellipse sing \[e ^{2}= 1 - b ^{2}/a ^{2}\] [when a>b] .. the distance between the focii is 2ae
using*
thanks :)

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