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heathernelly

  • 3 years ago

How far apart are the foci of an ellipse with a major axis of 26 feet and a minor axis of 24 feet?

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  1. begzat
    • 3 years ago
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    a^2+b^2=c^2

  2. heathernelly
    • 3 years ago
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    do i just put the numbers into the equation? :/ these are the answer choices:4 feet 5 feet 10 feet 20 feet

  3. begzat
    • 3 years ago
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    If the major axis is 26, then 2a is 26 and a is 13. If the minor axis is 24, then 2b is 24 and b is 12. Use the values of a and b to calculate c

  4. begzat
    • 3 years ago
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    do you know the Pythagorean triples or no

  5. heathernelly
    • 3 years ago
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    hmm no i don't

  6. heathernelly
    • 3 years ago
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    what do you mean 2a? a? 2b?

  7. begzat
    • 3 years ago
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    The distance between the focal points is 2a=26 and 2b=24

  8. begzat
    • 3 years ago
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    so plug here a^2+b^2=c^2

  9. siddarth95
    • 3 years ago
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    The length of the major axis is 2a and that of the minor axis is 2b like @begzat said. Find the eccentricity of the ellipse sing \[e ^{2}= 1 - b ^{2}/a ^{2}\] [when a>b] .. the distance between the focii is 2ae

  10. siddarth95
    • 3 years ago
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    using*

  11. heathernelly
    • 3 years ago
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    thanks :)

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