anonymous
  • anonymous
Find the equation of the circle with center at (3, 2) and through the point (5, 4).
Mathematics
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anonymous
  • anonymous
Find the equation of the circle with center at (3, 2) and through the point (5, 4).
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
I dont need the answer just a little help?
shaik0124
  • shaik0124
With a center at point (-1, -2), the formula will be (x+1)^2 + (y+2)^2 = r^2. As the point mentioned is on the circle, the distance from the canter point to this point must be the radius r. With the point (15,-2) on the circle, the distance from this point to the center is 16. The radius is therefore 16. The formula is therefore: (x+1)^2 + (y+2)^2 = 16^2 or (x+1)^2 + (y+2)^2 = 256
anonymous
  • anonymous
Thank you!! I understand it better now.

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shaik0124
  • shaik0124
ok :)

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