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anonymous
 3 years ago
Find the equation of the circle with center at (3, 2) and through the point (5, 4).
anonymous
 3 years ago
Find the equation of the circle with center at (3, 2) and through the point (5, 4).

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I dont need the answer just a little help?

shaik0124
 3 years ago
Best ResponseYou've already chosen the best response.0With a center at point (1, 2), the formula will be (x+1)^2 + (y+2)^2 = r^2. As the point mentioned is on the circle, the distance from the canter point to this point must be the radius r. With the point (15,2) on the circle, the distance from this point to the center is 16. The radius is therefore 16. The formula is therefore: (x+1)^2 + (y+2)^2 = 16^2 or (x+1)^2 + (y+2)^2 = 256

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you!! I understand it better now.
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