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BBrein
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Find the equation of the circle with center at (3, 2) and through the point (5, 4).
 one year ago
 one year ago
BBrein Group Title
Find the equation of the circle with center at (3, 2) and through the point (5, 4).
 one year ago
 one year ago

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BBrein Group TitleBest ResponseYou've already chosen the best response.0
I dont need the answer just a little help?
 one year ago

shaik0124 Group TitleBest ResponseYou've already chosen the best response.0
With a center at point (1, 2), the formula will be (x+1)^2 + (y+2)^2 = r^2. As the point mentioned is on the circle, the distance from the canter point to this point must be the radius r. With the point (15,2) on the circle, the distance from this point to the center is 16. The radius is therefore 16. The formula is therefore: (x+1)^2 + (y+2)^2 = 16^2 or (x+1)^2 + (y+2)^2 = 256
 one year ago

BBrein Group TitleBest ResponseYou've already chosen the best response.0
Thank you!! I understand it better now.
 one year ago
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