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unheard

  • one year ago

Can someone help me find the slope and y intercept please? I'd really appreciate it. y= -1/3x + 3 -x + 3y = 9

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  1. mathstudent55
    • one year ago
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    The slope-intercept form of the equation of a line is y = mx + b where m = slope, and b = y-intercept

  2. shaik0124
    • one year ago
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    slope is-1/3 n y intercept is 3

  3. ash2326
    • one year ago
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    Standard form of a line with slope m and y-intercept c \[y=mx+c\] Let's compare this with the first equation \[y=-\frac 1 3 x+3\] Do you see any correspondence between the two equations? @unheard

  4. unheard
    • one year ago
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    Kind of, @ash2326 I'm honestly terrible at slope.

  5. ash2326
    • one year ago
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    @shaik0124 Please don't give just answers, it won't help the user. Please explain how you got it

  6. shaik0124
    • one year ago
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    just compare two equations where m is slope and c is y intrcpt

  7. shaik0124
    • one year ago
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    ok aishwarya2326

  8. unheard
    • one year ago
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    I think I understand the comparing the equations.

  9. shaik0124
    • one year ago
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    good now corelate both n find values

  10. unheard
    • one year ago
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    I don't understand that o.o

  11. ash2326
    • one year ago
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    \[y=mx+c\] \[y=-\frac 13 x+3\] if in the first equation, we put m=-1/3 and c=3 We'll get the second one, won't we?

  12. unheard
    • one year ago
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    Yes. @ash2326

  13. ash2326
    • one year ago
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    So there you have m= slope =-1/3 and y intercept c= 3 That's comparing the two equations

  14. unheard
    • one year ago
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    Awesome, @ash2326 . Thanks so much. Could you help me with two more?

  15. ash2326
    • one year ago
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    Yeah, I could. If they are similar, you should try them first

  16. unheard
    • one year ago
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    No, the whole thing is part of a small project, but I am no good in Math, excpecially in slopes, haha. How would I graph the line in slope- intercept method? I just need to describe it.

  17. ash2326
    • one year ago
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    OK, I'll help you,but first close this question and post it as a new question. That way more users can help

  18. unheard
    • one year ago
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    Awesome, okay.

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