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anonymous
 3 years ago
find the derivative of f(x) = (3x^2  3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.
anonymous
 3 years ago
find the derivative of f(x) = (3x^2  3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 can u help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@onegirl hints has been given in the ques so what will u get after simplifying ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0after i put 2x over each term f(x) = 3x^2/2x – 3x/2x + 1/2x f(x) 3/2 x + 3/2 + 1/2x f’(x) = 3/2 + 0  1/2x^2 f’(x) = 3x^2 – 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0last step is wrong u forgot to write in denominator?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for f'(x) = 3x^2  1?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1\[f(x)=\frac{3}{2}x\frac{3}{2}+\frac{1}{2}x ^{1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it will be 3x^21/2x^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what do i do after that?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1\[f'(x)=\frac{3}{3}\frac{1}{2}x ^{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so thats my derivative?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Whoops. Typo. Should be 3/2 not 3/3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah thats your derivative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay ii guess not putting 2x^2 is why i got it wrong

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1You were supposed to put 2x UNDER each term

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Mertsj so i did it wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@zepdrix can u help please? did i do it right or wrong?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1362685192013:dwDo you understand this step? ~Splitting up the fractions. I wrote those ugly blobs to help show how we'll split it up.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea i understand that step

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1So the x's will divide in the middle term. Do you understand how to simplify the first term?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got (3x^2  3x + 1)/(2x)

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Yep. Now split it up into 3 fractions like your teacher said.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1ya you took a step backwards.. that was strange :c

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so i put 2x under each of those 3 fractions?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Put 2x UNDER each term. The first term is 3x^2

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1You didn't "get" (3x^2  3x + 1)/(2x). You STARTED with that :) The first step was to split it into 3 fractions.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so 3x^2/2x  3x/2x + 1/2x

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1yes, now simplify each fraction c: Don't combine them back together though! heh

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so i got 3x/2  3/2 + 1/2x after simplifying

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1k looks good c: Let's rewrite it in a way that will be easier to take a derivative of.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large f(x)=\frac{3x}{2}\frac{3}{2}+\color{orangered}{\frac{1}{2x}}\]In the last term, we can bring the x up to the numerator by applying a negative exponent to it.\[\large f(x)=\frac{3x}{2}\frac{3}{2}+\color{orangered}{\frac{x^{1}}{2}}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Let's pull those X's off of the fraction bar, it will be easier to read if we just have coefficients in front of our X's. \[\large f(x)=\frac{3x}{2}\frac{3}{2}+\frac{1\cdot x^{1}}{2} \qquad \rightarrow \qquad f(x)=\frac{3}{2}x\frac{3}{2}+\frac{1}{2}x^{1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so now i can just find the derivative of 3/2 x  3/2 + 1/2 x ^1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay i'll find the derivative thx!
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