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onegirl Group Title

find the derivative of f(x) = (3x^2 - 3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.

  • one year ago
  • one year ago

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  1. onegirl Group Title
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    @satellite73 can u help?

    • one year ago
  2. niksva Group Title
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    @onegirl hints has been given in the ques so what will u get after simplifying ?

    • one year ago
  3. onegirl Group Title
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    ok hold on

    • one year ago
  4. onegirl Group Title
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    after i put 2x over each term f(x) = 3x^2/2x – 3x/2x + 1/2x f(x) 3/2 x + 3/2 + 1/2x f’(x) = 3/2 + 0 - 1/2x^2 f’(x) = 3x^2 – 1

    • one year ago
  5. niksva Group Title
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    last step is wrong u forgot to write in denominator?

    • one year ago
  6. onegirl Group Title
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    what step?

    • one year ago
  7. onegirl Group Title
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    for f'(x) = 3x^2 - 1?

    • one year ago
  8. niksva Group Title
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    yeah

    • one year ago
  9. onegirl Group Title
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    ohh

    • one year ago
  10. onegirl Group Title
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    so 3x^2 -1/2x?

    • one year ago
  11. Mertsj Group Title
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    \[f(x)=\frac{3}{2}x-\frac{3}{2}+\frac{1}{2}x ^{-1}\]

    • one year ago
  12. niksva Group Title
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    it will be 3x^2-1/2x^2

    • one year ago
  13. onegirl Group Title
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    okay

    • one year ago
  14. onegirl Group Title
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    so what do i do after that?

    • one year ago
  15. niksva Group Title
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    it is ur answer

    • one year ago
  16. Mertsj Group Title
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    \[f'(x)=\frac{3}{3}-\frac{1}{2}x ^{-2}\]

    • one year ago
  17. onegirl Group Title
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    so thats my derivative?

    • one year ago
  18. Mertsj Group Title
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    Whoops. Typo. Should be 3/2 not 3/3

    • one year ago
  19. niksva Group Title
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    yeah thats your derivative

    • one year ago
  20. onegirl Group Title
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    okay ii guess not putting 2x^2 is why i got it wrong

    • one year ago
  21. niksva Group Title
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    yeah

    • one year ago
  22. onegirl Group Title
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    thx

    • one year ago
  23. Mertsj Group Title
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    You were supposed to put 2x UNDER each term

    • one year ago
  24. onegirl Group Title
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    yea i did

    • one year ago
  25. onegirl Group Title
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    @Mertsj so i did it wrong?

    • one year ago
  26. onegirl Group Title
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    @zepdrix can u help please? did i do it right or wrong?

    • one year ago
  27. zepdrix Group Title
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    |dw:1362685192013:dw|Do you understand this step? ~Splitting up the fractions. I wrote those ugly blobs to help show how we'll split it up.

    • one year ago
  28. onegirl Group Title
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    ok

    • one year ago
  29. onegirl Group Title
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    i see now

    • one year ago
  30. onegirl Group Title
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    yea i understand that step

    • one year ago
  31. zepdrix Group Title
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    So the x's will divide in the middle term. Do you understand how to simplify the first term?

    • one year ago
  32. onegirl Group Title
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    let me try

    • one year ago
  33. onegirl Group Title
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    i got (3x^2 - 3x + 1)/(2x)

    • one year ago
  34. Mertsj Group Title
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    Yep. Now split it up into 3 fractions like your teacher said.

    • one year ago
  35. zepdrix Group Title
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    ya you took a step backwards.. that was strange :c

    • one year ago
  36. onegirl Group Title
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    okay so i put 2x under each of those 3 fractions?

    • one year ago
  37. onegirl Group Title
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    i did?

    • one year ago
  38. Mertsj Group Title
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    Put 2x UNDER each term. The first term is 3x^2

    • one year ago
  39. zepdrix Group Title
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    You didn't "get" (3x^2 - 3x + 1)/(2x). You STARTED with that :) The first step was to split it into 3 fractions.

    • one year ago
  40. onegirl Group Title
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    ok so 3x^2/2x - 3x/2x + 1/2x

    • one year ago
  41. onegirl Group Title
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    Ohhh okay got u

    • one year ago
  42. Mertsj Group Title
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    There you go.

    • one year ago
  43. zepdrix Group Title
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    yes, now simplify each fraction c: Don't combine them back together though! heh

    • one year ago
  44. onegirl Group Title
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    ok

    • one year ago
  45. onegirl Group Title
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    hold on lol sorry

    • one year ago
  46. onegirl Group Title
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    ok so i got 3x/2 - 3/2 + 1/2x after simplifying

    • one year ago
  47. zepdrix Group Title
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    k looks good c: Let's rewrite it in a way that will be easier to take a derivative of.

    • one year ago
  48. onegirl Group Title
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    ok

    • one year ago
  49. zepdrix Group Title
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    \[\large f(x)=\frac{3x}{2}-\frac{3}{2}+\color{orangered}{\frac{1}{2x}}\]In the last term, we can bring the x up to the numerator by applying a negative exponent to it.\[\large f(x)=\frac{3x}{2}-\frac{3}{2}+\color{orangered}{\frac{x^{-1}}{2}}\]

    • one year ago
  50. zepdrix Group Title
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    Let's pull those X's off of the fraction bar, it will be easier to read if we just have coefficients in front of our X's. \[\large f(x)=\frac{3x}{2}-\frac{3}{2}+\frac{1\cdot x^{-1}}{2} \qquad \rightarrow \qquad f(x)=\frac{3}{2}x-\frac{3}{2}+\frac{1}{2}x^{-1}\]

    • one year ago
  51. onegirl Group Title
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    okay

    • one year ago
  52. onegirl Group Title
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    so now i can just find the derivative of 3/2 x - 3/2 + 1/2 x ^-1

    • one year ago
  53. zepdrix Group Title
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    yah sounds good.

    • one year ago
  54. onegirl Group Title
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    okay i'll find the derivative thx!

    • one year ago
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