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onegirl
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find the derivative of f(x) = (3x^2  3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.
 one year ago
 one year ago
onegirl Group Title
find the derivative of f(x) = (3x^2  3x + 1)/(2x). Directions, put 2x under each term and simplify. Then take the derivative.
 one year ago
 one year ago

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onegirl Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 can u help?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
@onegirl hints has been given in the ques so what will u get after simplifying ?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
ok hold on
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
after i put 2x over each term f(x) = 3x^2/2x – 3x/2x + 1/2x f(x) 3/2 x + 3/2 + 1/2x f’(x) = 3/2 + 0  1/2x^2 f’(x) = 3x^2 – 1
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
last step is wrong u forgot to write in denominator?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
what step?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
for f'(x) = 3x^2  1?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
so 3x^2 1/2x?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
\[f(x)=\frac{3}{2}x\frac{3}{2}+\frac{1}{2}x ^{1}\]
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
it will be 3x^21/2x^2
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
so what do i do after that?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
it is ur answer
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
\[f'(x)=\frac{3}{3}\frac{1}{2}x ^{2}\]
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
so thats my derivative?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Whoops. Typo. Should be 3/2 not 3/3
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
yeah thats your derivative
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay ii guess not putting 2x^2 is why i got it wrong
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
You were supposed to put 2x UNDER each term
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@Mertsj so i did it wrong?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix can u help please? did i do it right or wrong?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1362685192013:dwDo you understand this step? ~Splitting up the fractions. I wrote those ugly blobs to help show how we'll split it up.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
yea i understand that step
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
So the x's will divide in the middle term. Do you understand how to simplify the first term?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
let me try
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
i got (3x^2  3x + 1)/(2x)
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Yep. Now split it up into 3 fractions like your teacher said.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
ya you took a step backwards.. that was strange :c
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay so i put 2x under each of those 3 fractions?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Put 2x UNDER each term. The first term is 3x^2
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
You didn't "get" (3x^2  3x + 1)/(2x). You STARTED with that :) The first step was to split it into 3 fractions.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
ok so 3x^2/2x  3x/2x + 1/2x
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
Ohhh okay got u
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
There you go.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
yes, now simplify each fraction c: Don't combine them back together though! heh
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
hold on lol sorry
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
ok so i got 3x/2  3/2 + 1/2x after simplifying
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
k looks good c: Let's rewrite it in a way that will be easier to take a derivative of.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large f(x)=\frac{3x}{2}\frac{3}{2}+\color{orangered}{\frac{1}{2x}}\]In the last term, we can bring the x up to the numerator by applying a negative exponent to it.\[\large f(x)=\frac{3x}{2}\frac{3}{2}+\color{orangered}{\frac{x^{1}}{2}}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Let's pull those X's off of the fraction bar, it will be easier to read if we just have coefficients in front of our X's. \[\large f(x)=\frac{3x}{2}\frac{3}{2}+\frac{1\cdot x^{1}}{2} \qquad \rightarrow \qquad f(x)=\frac{3}{2}x\frac{3}{2}+\frac{1}{2}x^{1}\]
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
so now i can just find the derivative of 3/2 x  3/2 + 1/2 x ^1
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
yah sounds good.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay i'll find the derivative thx!
 one year ago
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