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Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
So you mean\[\frac{ d }{ dx }(\tan3x4x)*\frac{ d }{ dx }(3x)*\frac{ d }{ dx }(4x)\]?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
no the derivative of tan 3x  4x...the multiplying part is the directions
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
hold on wait its tan 3x  csc 4x
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
its tan 3x csc 4x i miss typed it
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
That's the answer you got or the correct answer?
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
And what part of the equation is inside the tan? Is it tan(3x)4x or tan(3x4x)
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
No not the correct answer i need to find the derivative of that and it says to multiply the derivatives of 3x and 4x into the promblem
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
its tan 3x  csc 4x thats how it written
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
@onegirl Please, post the right question. I confuse, too
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay hold on
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
let me edit my original question
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
there do you guys see it now?
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
yes. i think Twis7ed will guide you well.
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
Oh, ok, so\[\frac{ d }{ dx }(\tan 3x  \csc 4x)=\frac{ d }{ dx }\tan3x  \frac{ d }{ dx }\csc4x\] From that you know that \[\frac{ d }{ dx }\tan3x = 3\sec^2(3x)\] and that \[\frac{ d }{ dx }\csc4x=4\cot(4x)\csc(4x)\]so you end up with\[\frac{ d }{ dx }(\tan3x\csc4x)=3\sec^2(3x)+4\cot(4x)\csc(4x)\]
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
^Do you understand that?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
yes, so i dont have to multiply the derivatives of 3x and 4x into the whole problem?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
yes i understood what you wrote/
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
I'm not sure, what is the entire question?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
Okay so I found the derivative of that and my teacher told me to multiply 3x and 4x into it here is how i did it hold on
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
d/dx (tan(3)x  csc 4x = tan(3)  csc 4
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
i think i understnad where i went wrong now after seeing what you showed
 one year ago

Twis7ed Group TitleBest ResponseYou've already chosen the best response.2
ALright, just try to remember that when you have a trig function you usually use the chain rule with the function and then the function inside of it and it should be easy :)
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
okay thanks
 one year ago
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