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anonymous
 3 years ago
Find the derivative of f(x) tan 3x  csc 4x.
anonymous
 3 years ago
Find the derivative of f(x) tan 3x  csc 4x.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So you mean\[\frac{ d }{ dx }(\tan3x4x)*\frac{ d }{ dx }(3x)*\frac{ d }{ dx }(4x)\]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no the derivative of tan 3x  4x...the multiplying part is the directions

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hold on wait its tan 3x  csc 4x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its tan 3x csc 4x i miss typed it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's the answer you got or the correct answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And what part of the equation is inside the tan? Is it tan(3x)4x or tan(3x4x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No not the correct answer i need to find the derivative of that and it says to multiply the derivatives of 3x and 4x into the promblem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its tan 3x  csc 4x thats how it written

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@onegirl Please, post the right question. I confuse, too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me edit my original question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there do you guys see it now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes. i think Twis7ed will guide you well.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, ok, so\[\frac{ d }{ dx }(\tan 3x  \csc 4x)=\frac{ d }{ dx }\tan3x  \frac{ d }{ dx }\csc4x\] From that you know that \[\frac{ d }{ dx }\tan3x = 3\sec^2(3x)\] and that \[\frac{ d }{ dx }\csc4x=4\cot(4x)\csc(4x)\]so you end up with\[\frac{ d }{ dx }(\tan3x\csc4x)=3\sec^2(3x)+4\cot(4x)\csc(4x)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0^Do you understand that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, so i dont have to multiply the derivatives of 3x and 4x into the whole problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i understood what you wrote/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not sure, what is the entire question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so I found the derivative of that and my teacher told me to multiply 3x and 4x into it here is how i did it hold on

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0d/dx (tan(3)x  csc 4x = tan(3)  csc 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think i understnad where i went wrong now after seeing what you showed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ALright, just try to remember that when you have a trig function you usually use the chain rule with the function and then the function inside of it and it should be easy :)
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