anonymous
  • anonymous
Find the derivative of f(x) tan 3x - csc 4x.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
So you mean\[\frac{ d }{ dx }(\tan3x-4x)*\frac{ d }{ dx }(3x)*\frac{ d }{ dx }(4x)\]?
anonymous
  • anonymous
no the derivative of tan 3x - 4x...the multiplying part is the directions
anonymous
  • anonymous
hold on wait its tan 3x - csc 4x

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anonymous
  • anonymous
its tan 3x- csc 4x i miss typed it
anonymous
  • anonymous
That's the answer you got or the correct answer?
anonymous
  • anonymous
And what part of the equation is inside the tan? Is it tan(3x)-4x or tan(3x-4x)
anonymous
  • anonymous
No not the correct answer i need to find the derivative of that and it says to multiply the derivatives of 3x and 4x into the promblem
anonymous
  • anonymous
its tan 3x - csc 4x thats how it written
anonymous
  • anonymous
@onegirl Please, post the right question. I confuse, too
anonymous
  • anonymous
okay hold on
anonymous
  • anonymous
let me edit my original question
anonymous
  • anonymous
there do you guys see it now?
anonymous
  • anonymous
yes. i think Twis7ed will guide you well.
anonymous
  • anonymous
ok
anonymous
  • anonymous
Oh, ok, so\[\frac{ d }{ dx }(\tan 3x - \csc 4x)=\frac{ d }{ dx }\tan3x - \frac{ d }{ dx }\csc4x\] From that you know that \[\frac{ d }{ dx }\tan3x = 3\sec^2(3x)\] and that \[\frac{ d }{ dx }\csc4x=-4\cot(4x)\csc(4x)\]so you end up with\[\frac{ d }{ dx }(\tan3x-\csc4x)=3\sec^2(3x)+4\cot(4x)\csc(4x)\]
anonymous
  • anonymous
^Do you understand that?
anonymous
  • anonymous
it's the best
anonymous
  • anonymous
yes, so i dont have to multiply the derivatives of 3x and 4x into the whole problem?
anonymous
  • anonymous
yes i understood what you wrote/
anonymous
  • anonymous
I'm not sure, what is the entire question?
anonymous
  • anonymous
Okay so I found the derivative of that and my teacher told me to multiply 3x and 4x into it here is how i did it hold on
anonymous
  • anonymous
d/dx (tan(3)x - csc 4x = tan(3) - csc 4
anonymous
  • anonymous
i think i understnad where i went wrong now after seeing what you showed
anonymous
  • anonymous
ALright, just try to remember that when you have a trig function you usually use the chain rule with the function and then the function inside of it and it should be easy :)
anonymous
  • anonymous
okay thanks

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