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Is it:
\[4x^2\tan x\]

yes

\[\tan x=\sqrt{1-\sec ^2x}\]

That's using a Pythagorean identity.

ok

So you would be taking the derivative of
\[4x^2\sqrt{1-\sec ^2x}\]

okay i'll do that

ok

i got 4x(x + sin(2x)) sqrt(tan^2 (x)) csc (x) sec (x)