Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cntrywrtr

  • 2 years ago

can anyone explain to me how to figure this out?

  • This Question is Closed
  1. cntrywrtr
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Which element listed is more reactive than lithium and magnesium, but less reactive than potassium?

  2. abb0t
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sodium. you can refer to your periodcic table, and atomic size, availability of it's electron on orbital.

  3. cntrywrtr
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I know the answer. I don't know how to come to that conclusion. And I don't know what you mean by availability of it's electron orbital

  4. abb0t
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    bigger shell, farther away from nucleus. less energy to remove that valence electron from potassium than from sodium, leading to increased reactivity.

  5. cntrywrtr
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay. =/

  6. aaronq
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you're talking about the metals being elemental (not in a compound) you could look at values for their 1st ionization energies, which would give you quantitative measurement of their ability to lose their valence electron(s). http://www.chemicool.com/ or http://chemreference.com/

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.