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|dw:1362695099329:dw|

I need to know step by step on how to solve this.

@jim_thompson5910 Please help. :(

is this a right triangle?

|dw:1362695278150:dw|

ok thank you

|dw:1362695556789:dw|

this is because all angles must add to 180
notice how 45 + 45 + 90 = 180

so we have a 45-45-90 triangle which means that the two legs are congruent

|dw:1362695629297:dw|

|dw:1362695698593:dw|

if you already figured out the hypotenuse's are the same, why'd you do all that work up there?

the legs are the same, not the hypotenuses

oh. Should I put down the equations you did to get a decent grade?

alright, did you see how I figured out how x = sqrt(2) ?

with me so far?

can you write it down, like.."step 1, step 2" to make it more simple?

|dw:1362696451678:dw|

would I write that down on a paper?

yeah if you wanted to, you could also use the template above as a shortcut

this template
|dw:1362696580301:dw|

Ugh..I'll show you what I have on my paper and you say if it's correct or not..

|dw:1362696649159:dw|

ok good so far, you just have shown that the missing angle is 45 degrees

oh and you threw in x = sqrt(2)

okay

the next thing you need to show is how to get y

there are 2 ways to do it: use the template above or the pythagorean theorem

both ways are shown in this post

can you show them again. you can copy them

here is the pythagorean theorem method

sound good?

Yeah. Sorry, I was off the computer. Taking a break. :P

Wait..Y=2? @jim_thompson5910

yes, y = 2

|dw:1362701799670:dw|

could I make it look like this?|dw:1362701962485:dw|

from the one thing you showed me? instead of putting down "sqrt"?

yes you could do it that way (it's a bit cleaner looking)

just a question.. How does it equal y?

what do you mean?

nevermind I think I understand.

are you sure?

alright, I'm glad it's (sorta) making sense

so, x= sqrt2? It can't be simplified?

no it cannot

that's as simple as it gets for x

okay, can you help me with 2 more? Or no?

sure I can help

what's your question

the second one explains the same thing, but the problem is different.

I'll draw it

alright

|dw:1362702888077:dw|

:/

the legs are equal (we have another 45-45-90 triangle)

so y = x

would I write down that y=x?

use the pythagorean theorem to get
|dw:1362703031520:dw|

then you plug in y = x
|dw:1362703073963:dw|

and you solve for x

is that " X^2 + X^2"?

where did the y go?

y = x
so y and x are the same

ohh. I get ya. How do I solve for X for this?

so you can replace y with x

How do i solve for x?

well the two x^2 terms add up to 2x^2

so you will have
2x^2 = 450
then what?

well, I'd think you'd divide the 450 by 2 but it's squared..so, I don't know..

yes,
2x^2 = 450
x^2 = 450/2
x^2 = 225
x = sqrt(225)
x = 15

so both x and y are 15 (since y = x)

Oh, I get it. Thankyou. :)

here's the 3rd one..

|dw:1362704401057:dw|

this is another 45-45-90 triangle (the legs are congruent)

Okay

so what does that mean for the value of y?

it's bigger

yes and what else

how can you find the value of y?

isn't it a^2 +b^2=c^2?

very good

replace a with sqrt(5)
replace b with sqrt(5)
and you want to solve for c

I know. :)

ok great

Do I actually solve sqrt5^2 + sqrt5^2 in the calculator?

well the square of the square roots cancel each other out

so (sqrt(5))^2 = 5

so you are left with 5 + 5 which turns into 10

so c^2 = 10

I'm confused. How did you get 5+5?

|dw:1362706218096:dw|

so that's how I got 2 five terms being added

wouldn't I replace C with Y?

you would

so y^2 = 10

making
|dw:1362706377944:dw|

is that it for that problem?

yes, you found y, so you're done

Oh, I'm so sorry. but I don't get this other one. Can you help me with it? c:

sure

|dw:1362707591687:dw|

hullo?

sry was afk for a sec

were you able to get anywhere with this at all?

No. :/

I think Y = 2 sqrt 3?

sry i had to go afk, but I'm back

y is actually 2
the legs are not congruent

x = 2*y
x = 2*2
x =4

the reason how I know y is 2 is from this template
|dw:1362709753724:dw|

um, 60 degrees is down below and down below, its 2 sqrt3

|dw:1362710294844:dw|

you missed the 3?

I mean 2

the 2*sqrt(3) is above though isnt it?

I just showed you the diagram. :P

but in this one, the 2*sqrt(3) is above
|dw:1362710579138:dw|

Are you supposed to change what I showed you?

no i just copied what you drew

you're mixing up everything I just drew and you know that. ._.

look up at the picture again..

yeah i see the new one, but you drew a totally different one

or is it a case the second one is the correct one and the first one was a typo?

OH I'm sorry!

yeah i was like...what in the world lol

that was my fault.

its fine, so which one is it?

the second one is correct.

ok one sec

are you gonna help? I don't have all day.

|dw:1362712584316:dw|

the value of x is exactly half that of the hypotenuse

That's correct. xP Lol.

yeah just wanted to make sure and put it up again

so x = 2*sqrt(3)/2 = sqrt(3)

which means
|dw:1362712746325:dw|

wait stop

ok whats up

is it 2 times sqrt 3/2?

yes

the 2 terms cancel

so I write this down? x = 2*sqrt(3)/2 = sqrt(3)

yes and that will give you the value of x

Just to make sure we're on the same topic..|dw:1362713238955:dw|

yep

is that how it should be shown?

yes you have it correct, so now that you have x, you can find y

y = x*sqrt(3)
y = sqrt(3)*sqrt(3)
y = 3

so, Y= 3 and X= Sqrt 3

yes good

wanna help me with one more please? :D

ok one more

:) Thanks!

sure thing

|dw:1362714107413:dw|

|dw:1362714258167:dw|

x = 2*12
x = 24
since the hypotenuse is double the shorter leg in a 30-60-90 triangle

y = 12*sqrt(3) because of the template given above

where'd you get the 2 in the first one?

in general, with any 30-60-90 triangle
the hypotenuse is twice as long as the shorter leg

oh, so that's why it's 2 x 24..Okay,

2 * 12 = 24, but yeah you have it

what's Y?

y = 12*sqrt(3)

sry mixed up the 30 and the 60

|dw:1362714824453:dw|

What is the answer for Y? I got 20..:/

20 is incorect

incorrect*

|dw:1362714907609:dw|

you can't simplify it?

that's as simplified as it gets

how did you find y?

in the template above, do you see how the longer leg is x*sqrt(3) ?

ohhh.. now I get it.

Thankyou ! :)

ok I would write that template down, it's very handy

also the 45-45-90 template as well

thankyou for helping me

you're welcome, sry for being afk a lot lol