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help123please.

  • one year ago

Using the image at http://fotos.fotoflexer.com/307d9591812479fea36cb26258913578.jpg Answer these questions: Do you think the test was too hard for the students? Explain. Would you expect the mean to be above or below the median? Explain.

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  1. help123please.
    • one year ago
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    @Kitt020912

  2. help123please.
    • one year ago
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    @timo86m

  3. timo86m
    • one year ago
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    Do you think the test was too hard for the students? Explain. NO because it looks like some even got 102%

  4. help123please.
    • one year ago
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    Hmm. Okay,thanks!

  5. help123please.
    • one year ago
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    What about the second question?

  6. timo86m
    • one year ago
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    got no idea.

  7. help123please.
    • one year ago
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    Okay.

  8. timo86m
    • one year ago
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    http://answers.yahoo.com/question/index?qid=20110523160727AA4i32v that is exactly what i was thinking it impossible to find mean.

  9. help123please.
    • one year ago
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    Impossible?

  10. timo86m
    • one year ago
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    Well i guess we can make an estimate (72+88+96+102)/4 Just an estimate and see if it higher than medium

  11. help123please.
    • one year ago
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    Yes, but I have to explain.

  12. help123please.
    • one year ago
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    O well. Thats alright - - no worries.

  13. timo86m
    • one year ago
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    explain that you assume that averaging the quartiles will give you an estimated mean :)

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