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 one year ago
Using the image at http://fotos.fotoflexer.com/307d9591812479fea36cb26258913578.jpg
Answer these questions:
Do you think the test was too hard for the students? Explain.
Would you expect the mean to be above or below the median? Explain.
 one year ago
Using the image at http://fotos.fotoflexer.com/307d9591812479fea36cb26258913578.jpg Answer these questions: Do you think the test was too hard for the students? Explain. Would you expect the mean to be above or below the median? Explain.

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timo86m
 one year ago
Best ResponseYou've already chosen the best response.1Do you think the test was too hard for the students? Explain. NO because it looks like some even got 102%

help123please.
 one year ago
Best ResponseYou've already chosen the best response.0Hmm. Okay,thanks!

help123please.
 one year ago
Best ResponseYou've already chosen the best response.0What about the second question?

timo86m
 one year ago
Best ResponseYou've already chosen the best response.1http://answers.yahoo.com/question/index?qid=20110523160727AA4i32v that is exactly what i was thinking it impossible to find mean.

timo86m
 one year ago
Best ResponseYou've already chosen the best response.1Well i guess we can make an estimate (72+88+96+102)/4 Just an estimate and see if it higher than medium

help123please.
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but I have to explain.

help123please.
 one year ago
Best ResponseYou've already chosen the best response.0O well. Thats alright   no worries.

timo86m
 one year ago
Best ResponseYou've already chosen the best response.1explain that you assume that averaging the quartiles will give you an estimated mean :)
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