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help123please.
 2 years ago
Using the image at http://fotos.fotoflexer.com/307d9591812479fea36cb26258913578.jpg
Answer these questions:
Do you think the test was too hard for the students? Explain.
Would you expect the mean to be above or below the median? Explain.
help123please.
 2 years ago
Using the image at http://fotos.fotoflexer.com/307d9591812479fea36cb26258913578.jpg Answer these questions: Do you think the test was too hard for the students? Explain. Would you expect the mean to be above or below the median? Explain.

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timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1Do you think the test was too hard for the students? Explain. NO because it looks like some even got 102%

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm. Okay,thanks!

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0What about the second question?

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1http://answers.yahoo.com/question/index?qid=20110523160727AA4i32v that is exactly what i was thinking it impossible to find mean.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1Well i guess we can make an estimate (72+88+96+102)/4 Just an estimate and see if it higher than medium

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, but I have to explain.

help123please.
 2 years ago
Best ResponseYou've already chosen the best response.0O well. Thats alright   no worries.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.1explain that you assume that averaging the quartiles will give you an estimated mean :)
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