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Tahmina

  • one year ago

systems help!

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  1. kropot72
    • one year ago
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    The two lines intersect at the point (-2, 1).

  2. Tahmina
    • one year ago
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    thanks for coming !

  3. timo86m
    • one year ago
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    y=mx+b use that formula use it twice and make the y and x equal but vary the m and b -2=m_1*1+b_1 -2=m_2*1+b_2 that ought to work i think.

  4. Tahmina
    • one year ago
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    i dont understand!

  5. timo86m
    • one year ago
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    make the y and x equal to (-2,1).

  6. ghazi
    • one year ago
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    from a point there could be infinitely many lines can pass through

  7. ghazi
    • one year ago
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    so it could be so just write y=mx+c and put y=1 and x=-2

  8. Tahmina
    • one year ago
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    so :1=m(-2)+b

  9. Tahmina
    • one year ago
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    ?

  10. ghazi
    • one year ago
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    it could be anything like y=x+3

  11. Tahmina
    • one year ago
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    oh okay

  12. Tahmina
    • one year ago
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    i need another equation!

  13. tafkas77
    • one year ago
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    You need another equation?

  14. tafkas77
    • one year ago
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    Or another explanation?

  15. Tahmina
    • one year ago
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    i need to label line and bi have line a which is y=x+3 now i need another equation!

  16. Tahmina
    • one year ago
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    need to label line a and b and i have line a already

  17. Tahmina
    • one year ago
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    let me scan the paper for you so it will help u okay

  18. tafkas77
    • one year ago
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    Wow, I was just about to ask you! :) Okay! :)

  19. Tahmina
    • one year ago
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    sorry cofee fell on it butll make sure ill show u just give me 2 minutes okay! :)

  20. tafkas77
    • one year ago
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    Sure! Take your time. :)

  21. Tahmina
    • one year ago
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    i think this is it!

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  22. Tahmina
    • one year ago
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    the second questions says what is the quation of each line u drew in problem 5? explain how u wrote each equation!

  23. tafkas77
    • one year ago
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    Hmm, just a sec, Tahmina. I must go calm my dog down (she's scared of thunder lol). But I have reviewed your question. :)

  24. Tahmina
    • one year ago
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    okay but i need u so please hurry! i have to got to bed its kinda getting late and i have school and i need to get enough sleep! thanks!

  25. Tahmina
    • one year ago
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    :)

  26. Tahmina
    • one year ago
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    what happened? :(

  27. Tahmina
    • one year ago
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    u suddenly were typing then poof ur gone oh tafkas i really need ur help please!

  28. Tahmina
    • one year ago
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    yeah theres u go ur typing again :) yay! :)

  29. tafkas77
    • one year ago
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    Poor dog! :) Arrgh... Pick any two points that you made, then use this calculator: http://www.miniwebtool.com/slope-intercept-form-calculator/ It will also show you the steps.

  30. tafkas77
    • one year ago
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    sorry about that. :/

  31. Tahmina
    • one year ago
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    im bad at this i tried this kind athying! sorry about that!

  32. tafkas77
    • one year ago
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    The points on your line that I would use are (-2, 1) and (0,3)

  33. tafkas77
    • one year ago
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    ONce you plug in those values, it will create the equation that you need.

  34. Tahmina
    • one year ago
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    but i dont have another coordinates can u show me im confused and tired :(

  35. tafkas77
    • one year ago
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    here, I plugged it in for you: http://www.miniwebtool.com/slope-intercept-form-calculator/?x1=-2&y1=1&x2=0&y2=3

  36. Tahmina
    • one year ago
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    thansk! i need line b now

  37. Tahmina
    • one year ago
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    please!

  38. tafkas77
    • one year ago
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    Okay, line b must be parallel. do point slope form: y - y1 = m(x - x1) and plug in your values: y - (1) = 1(x - (-2)) y - 1 = x + 2 y = x +3 since your slope is one, you can have literally anything for your next line: y = x + 5 got it?

  39. Tahmina
    • one year ago
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    oh okay! i was gonna ask u that!

  40. Tahmina
    • one year ago
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    sam slope but difrent y itercep tno wits coming back to me ohhh

  41. tafkas77
    • one year ago
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    Great! So you think you got it, now?

  42. Tahmina
    • one year ago
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    yeah! thanks! for all ur help1

  43. tafkas77
    • one year ago
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    Awesome! You're welcome, Tahmina. You know I don't mind helping you. :) Oh, there's the dog again... :)

  44. Tahmina
    • one year ago
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    and the lightining?

  45. tafkas77
    • one year ago
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    Ha ha, it freaks her out. She's not a chihuahua, but she shakes like one when she hears thunder XD

  46. Tahmina
    • one year ago
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    can u help me with another problem!?

  47. Tahmina
    • one year ago
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    |dw:1362706517622:dw|

  48. Tahmina
    • one year ago
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    hello?

  49. Tahmina
    • one year ago
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    :)

  50. tafkas77
    • one year ago
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    Let's get rid of "y." The second equation can be simplified. Divide all those terms in the second equation by 4: 2x+3y=2 (24x+4y=12)/4 --> new equation: 6x + y = 3 NEW SYSTEM: 2x+3y=2 6x + y = 3 multiply second equation by -3 to get rid of the y terms. NEW SYSTEM: 2x+3y=2 -18x -3y = -9 ____________________________________ (add the equations) -16x = -7 x =....... Do you understand this?

  51. Tahmina
    • one year ago
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    so the answer is c?

  52. Tahmina
    • one year ago
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    thanks!

  53. Tahmina
    • one year ago
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    tgt bye ! have to pray ans take a shower see u next time!

  54. tafkas77
    • one year ago
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    Yes! :) See you next time! :D

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