spidergirl51
(5x8) (2x5)



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math456
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5x(2x5)8(2x5) < try to solve this

spidergirl51
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um

math456
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use multiplication

spidergirl51
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okay i got 10x25 16x+40

andrea408
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10x^225x16x+25
which would be
10x^241x+25

math456
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great now solve further..

johnweldon1993
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Correct but remember 10x is 10 x ²

spidergirl51
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um

spidergirl51
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idk what to do now

math456
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yea when u multiply x's it becomes square

math456
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x.x=x^2

johnweldon1993
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When you multiply 2 numbers with x's the x's multiply too...which becomes x times x which is x squared...or x²

spidergirl51
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10x2

spidergirl51
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and then what

spidergirl51
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what about the 16x

spidergirl51
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4x2

math456
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now u hv 10x^241x+25.. after adding x's

spidergirl51
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i mean 6x2

johnweldon1993
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16x stays the same...do you have any other x's? ***you cannot combine x² and x.

spidergirl51
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oh

johnweldon1993
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wait perhaps I've looked wrong let me do this out

spidergirl51
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so its
10x2 41x+25

johnweldon1993
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(5x8) (2x5)
10x²  25x  16x + 40
so yes 10x² 41x + 40

spidergirl51
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i have like 13 problems like these

math456
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did u get some idea how to do it?

spidergirl51
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so thats your final answer

math456
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Use the FOIL method i used above for this e.g

spidergirl51
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(7w+5)(11w3)

math456
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let me do it over:
5x(2x5)8(2x5)
10x^225x16x+40
10x^241x+40

spidergirl51
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so 77w2+55w33w15

math456
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yea use the same trick with this:
7w(11w3)+5(11w3) < they just replaced x with w's

spidergirl51
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is that right

math456
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u got first one right 7w x 3 = 21w

math456
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so it will be 77w^221w+55w15
77w^2+34w15

spidergirl51
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yup
the next one is *b2)(b2b+1)

math456
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try it..

math456
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b(b^2b1)2(b^2b+1)

spidergirl51
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um

math456
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its not tht hard, give it a try

spidergirl51
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i got 2b22b1b2b22b+2

math456
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ur second part is right..

spidergirl51
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my first part is wrong

math456
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when u multiply bxb^2 it will be b^3

spidergirl51
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so its b3

math456
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right!

math456
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same goes with the next one.. u just add power to the variable when u multiply

spidergirl51
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so what will it look i like

math456
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b(b^2b1)2(b^2b+1)
\[b ^{3}b ^{2}b2b ^{2}+2b2\]

spidergirl51
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can you solve that