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yaro99

  • 3 years ago

Having trouble with the particular solution: y''+4y'+8y=2cos(2t)+sin(2t)

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  1. Xavier
    • 3 years ago
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    Guess Acos(2t)+Bsin(2t)

  2. yaro99
    • 3 years ago
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    I tried \[y_p=A \cos 2t+B \sin 2t\] and plugged in its derivatives, but I ended up with A=2/13 and B=3/13, but in the answer they are A=0 and B=1/4

  3. yaro99
    • 3 years ago
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    Oops I the 2 in 2t when differentiating. That's probably it, gonna try it now.

  4. yaro99
    • 3 years ago
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    I neglected* the 2 in 2t

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