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Is that right so far?

yes looks right. so far.

Okay, so this is what I got for my integration: \[\frac{ -e ^{-6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }+c\]

and then using that u(0)=8, I found that c=-0.125.

so then I end up with \[\frac{ -e ^{-6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }-0.125\]

so then my final answer was u(t)=\[\frac{ 1 }{ 6 }\ln(\frac{ 3 }{ 4 }e ^{8t}-\frac{ 3 }{ 4 })\]

but the book says that isn't the right answer

hmm well i also got c same as u.. well what answer book says?

well i am not sure but the way u solved question looks fine and the answer should be the one u got..

hmmm. Okay. I'll ask the tutor at 8. Thanks anyway :)