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anonymous
 3 years ago
calc II separable equation, please help :)
anonymous
 3 years ago
calc II separable equation, please help :)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ du }{ dt }=e ^{6u+8t}\] given that u(0)=8. So this is how I set it up \[\int\limits_{}^{}e ^{6u}du=\int\limits_{}^{}e ^{8t}dt\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is that right so far?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes looks right. so far.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, so this is what I got for my integration: \[\frac{ e ^{6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then using that u(0)=8, I found that c=0.125.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I actually have already worked through this problem, but I got the wrong answer at the end so I'm trying to figure out where I'm going wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then I end up with \[\frac{ e ^{6u} }{ 6 }=\frac{ e ^{8t} }{ 8 }0.125\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then my final answer was u(t)=\[\frac{ 1 }{ 6 }\ln(\frac{ 3 }{ 4 }e ^{8t}\frac{ 3 }{ 4 })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but the book says that isn't the right answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm well i also got c same as u.. well what answer book says?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, it's actually webwork, so it just tells me that my answer is wrong, I'm not sure what the right answer is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm thinking something must be wrong with the way I'm doing the algebra to rearrange it in terms of u(t)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i am not sure but the way u solved question looks fine and the answer should be the one u got..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm. Okay. I'll ask the tutor at 8. Thanks anyway :)
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