A ball is dropped from a height of 10 feet and bounces. Each bounce is 3/4 of the height of the bounce before. Thus, after the ball hits the floor for the first time, the ball rises to a height of 10(3/4) = 7.5 feet, and after it hits the floor a second time, it rises to a height of 7.5(3/4) = 10(3/4)^2 = 5.625 feet. (Assume g = 32 ft/sec2 and that there is no air resistance.)
(a) Find an expression for the height to which the ball rises after it hits the floor for the nth time.
Find the total vertical distance, D, the ball has traveled when it hits the floor for the fourth time.

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

hn= 10(3/4)^n but i don't know how to find the total vertical distance, D

I know part (a) but i dont know the second part

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.