Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
V(r)=  a e^2 lambda exp(r/p)
 +
4 pi epilson r
 one year ago
 one year ago
V(r)=  a e^2 lambda exp(r/p)  + 4 pi epilson r
 one year ago
 one year ago

This Question is Closed

modphysnoobBest ResponseYou've already chosen the best response.0
show that force can be expressed as F(r) = a e^2 ((r_0)^2/r)  4 pi epilson r_0^2 + exp( r r_0/ rho))
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
so do I just take derivative
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
\[ V(r) = \frac{ae^2}{4\pi \epsilon_0 r^2} + \lambda e^{r/p} \]?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
Yes, \[ \vec{F} = \vec{\nabla} V \]
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
In your case, since the potential is a function only of r, \[ \vec{F} = \frac{dV}{dr} \hat{r} \]
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
so , I get \[\frac{a e^2}{2 \pi r^3 \epsilon }\frac{e^{\frac{r}{p}} \lambda }{p}\]
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
which must be equal to give F
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
I don't know... your notation is rather confusing to me so I'm not quite sure what it says.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.