A community for students.
Here's the question you clicked on:
 0 viewing
modphysnoob
 2 years ago
V(r)=  a e^2 lambda exp(r/p)
 +
4 pi epilson r
modphysnoob
 2 years ago
V(r)=  a e^2 lambda exp(r/p)  + 4 pi epilson r

This Question is Closed

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0show that force can be expressed as F(r) = a e^2 ((r_0)^2/r)  4 pi epilson r_0^2 + exp( r r_0/ rho))

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0so do I just take derivative

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.0\[ V(r) = \frac{ae^2}{4\pi \epsilon_0 r^2} + \lambda e^{r/p} \]?

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, \[ \vec{F} = \vec{\nabla} V \]

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.0In your case, since the potential is a function only of r, \[ \vec{F} = \frac{dV}{dr} \hat{r} \]

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0so , I get \[\frac{a e^2}{2 \pi r^3 \epsilon }\frac{e^{\frac{r}{p}} \lambda }{p}\]

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0which must be equal to give F

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know... your notation is rather confusing to me so I'm not quite sure what it says.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.