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Tuhu

  • 3 years ago

verify tanΘ-secΘ = cosΘ/1+sinΘ

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  1. Meinme
    • 3 years ago
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    rationalise cosa/1+sin a and youll get the right part of equation

  2. Tuhu
    • 3 years ago
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    |dw:1362720006791:dw|

  3. Tuhu
    • 3 years ago
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    Please explain briefly TT_TT

  4. Meinme
    • 3 years ago
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    k here it goes do you know how to rationalise

  5. Tuhu
    • 3 years ago
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    NO

  6. Meinme
    • 3 years ago
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    okay then multiply in the numerator and denominator by 1-sinx and see if you get it now

  7. abb0t
    • 3 years ago
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    \[\tan(\theta) = \frac{ \sin(\theta) }{ \cos(\theta) }, \sec(\theta) = \frac{ 1 }{ \cos(\theta) }\] use the identities i provided to finish the proof.

  8. abb0t
    • 3 years ago
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    combine like terms. etc. follow your algebra rules to combine fractions and so forth.

  9. Directrix
    • 3 years ago
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    @Tuhu ---> Are the signs correctly posted on this --> tanΘ-secΘ = cosΘ/1+sinΘ

  10. Tuhu
    • 3 years ago
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    Yep, ^^ don't worry i'm done with this :||

  11. Directrix
    • 3 years ago
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    What do you mean? I am about to verify it. It is fairly short.

  12. abb0t
    • 3 years ago
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    time to go home.

  13. Directrix
    • 3 years ago
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    The signs on the problem are correct, right?

  14. Tuhu
    • 3 years ago
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    Yes

  15. Directrix
    • 3 years ago
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    Great. See you later.

  16. Directrix
    • 3 years ago
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  17. Directrix
    • 3 years ago
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  18. Directrix
    • 3 years ago
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    This statement does not appear to be a trigonometric identity. @Tuhu

  19. Tuhu
    • 3 years ago
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    Really? umm you guys are so helpful ^^ I really like drawing compare to math because i suck solving problems -_____-|dw:1362726331057:dw|

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