verify tanΘ-secΘ = cosΘ/1+sinΘ

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verify tanΘ-secΘ = cosΘ/1+sinΘ

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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rationalise cosa/1+sin a and youll get the right part of equation
|dw:1362720006791:dw|
Please explain briefly TT_TT

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k here it goes do you know how to rationalise
NO
okay then multiply in the numerator and denominator by 1-sinx and see if you get it now
\[\tan(\theta) = \frac{ \sin(\theta) }{ \cos(\theta) }, \sec(\theta) = \frac{ 1 }{ \cos(\theta) }\] use the identities i provided to finish the proof.
combine like terms. etc. follow your algebra rules to combine fractions and so forth.
@Tuhu ---> Are the signs correctly posted on this --> tanΘ-secΘ = cosΘ/1+sinΘ
Yep, ^^ don't worry i'm done with this :||
What do you mean? I am about to verify it. It is fairly short.
time to go home.
The signs on the problem are correct, right?
Yes
Great. See you later.
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This statement does not appear to be a trigonometric identity. @Tuhu
Really? umm you guys are so helpful ^^ I really like drawing compare to math because i suck solving problems -_____-|dw:1362726331057:dw|

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