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verify tanΘ-secΘ = cosΘ/1+sinΘ

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rationalise cosa/1+sin a and youll get the right part of equation
Please explain briefly TT_TT

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k here it goes do you know how to rationalise
okay then multiply in the numerator and denominator by 1-sinx and see if you get it now
\[\tan(\theta) = \frac{ \sin(\theta) }{ \cos(\theta) }, \sec(\theta) = \frac{ 1 }{ \cos(\theta) }\] use the identities i provided to finish the proof.
combine like terms. etc. follow your algebra rules to combine fractions and so forth.
@Tuhu ---> Are the signs correctly posted on this --> tanΘ-secΘ = cosΘ/1+sinΘ
Yep, ^^ don't worry i'm done with this :||
What do you mean? I am about to verify it. It is fairly short.
time to go home.
The signs on the problem are correct, right?
Great. See you later.
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This statement does not appear to be a trigonometric identity. @Tuhu
Really? umm you guys are so helpful ^^ I really like drawing compare to math because i suck solving problems -_____-|dw:1362726331057:dw|

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