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experimentX Group TitleBest ResponseYou've already chosen the best response.2
reduce y in to this from (px + q)^2 + r
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
where \[y^2=ax^2+bx+c\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
sry i meant y^2
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
do the same .. it wouldn't make any difference
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[1/a(x+b/2a)^2b^2/4a+c/a
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[1/a(x+b/2a)^2b^2/4a+c/a\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
i tried a euclidian sub of t \[t=y+x\sqrt a\]
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
yeah .. then substitute u = Sqrt(a)(x + b/x) should be of the form dw:1362742001381:dw
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
yeah to the first post or euclidean?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
do you agree with the sub of\[ t=y+x\sqrt{a}\]
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
where did you get that y ... there is no such y.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
check your equation again ... don't put that y there ... there is no y involved. I think you are confused.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
i have to go now but i 'll try it
 one year ago
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