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experimentX
 one year ago
Best ResponseYou've already chosen the best response.2reduce y in to this from (px + q)^2 + r

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0where \[y^2=ax^2+bx+c\]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2do the same .. it wouldn't make any difference

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0\[1/a(x+b/2a)^2b^2/4a+c/a

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0\[1/a(x+b/2a)^2b^2/4a+c/a\]

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0i tried a euclidian sub of t \[t=y+x\sqrt a\]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2yeah .. then substitute u = Sqrt(a)(x + b/x) should be of the form dw:1362742001381:dw

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0yeah to the first post or euclidean?

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0do you agree with the sub of\[ t=y+x\sqrt{a}\]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2where did you get that y ... there is no such y.

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2check your equation again ... don't put that y there ... there is no y involved. I think you are confused.

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0i have to go now but i 'll try it
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