A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
\[\int _a^b \frac{dx}{y}\],where \[ y^2=ax^2+bx+c\]
anonymous
 3 years ago
\[\int _a^b \frac{dx}{y}\],where \[ y^2=ax^2+bx+c\]

This Question is Closed

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2reduce y in to this from (px + q)^2 + r

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where \[y^2=ax^2+bx+c\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2do the same .. it wouldn't make any difference

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[1/a(x+b/2a)^2b^2/4a+c/a

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[1/a(x+b/2a)^2b^2/4a+c/a\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i tried a euclidian sub of t \[t=y+x\sqrt a\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2yeah .. then substitute u = Sqrt(a)(x + b/x) should be of the form dw:1362742001381:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah to the first post or euclidean?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you agree with the sub of\[ t=y+x\sqrt{a}\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2where did you get that y ... there is no such y.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2check your equation again ... don't put that y there ... there is no y involved. I think you are confused.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have to go now but i 'll try it
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.