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Jonask

  • 3 years ago

\[\int _a^b \frac{dx}{y}\],where \[ y^2=ax^2+bx+c\]

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  1. experimentX
    • 3 years ago
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    reduce y in to this from (px + q)^2 + r

  2. Jonask
    • 3 years ago
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    where \[y^2=ax^2+bx+c\]

  3. Jonask
    • 3 years ago
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    sry i meant y^2

  4. experimentX
    • 3 years ago
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    do the same .. it wouldn't make any difference

  5. Jonask
    • 3 years ago
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    \[1/a(x+b/2a)^2-b^2/4a+c/a

  6. Jonask
    • 3 years ago
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    \[1/a(x+b/2a)^2-b^2/4a+c/a\]

  7. Jonask
    • 3 years ago
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    i tried a euclidian sub of t \[t=y+x\sqrt a\]

  8. experimentX
    • 3 years ago
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    yeah .. then substitute u = Sqrt(a)(x + b/x) should be of the form |dw:1362742001381:dw|

  9. Jonask
    • 3 years ago
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    yeah to the first post or euclidean?

  10. experimentX
    • 3 years ago
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    ??

  11. Jonask
    • 3 years ago
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    do you agree with the sub of\[ t=y+x\sqrt{a}\]

  12. experimentX
    • 3 years ago
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    where did you get that y ... there is no such y.

  13. experimentX
    • 3 years ago
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    check your equation again ... don't put that y there ... there is no y involved. I think you are confused.

  14. Jonask
    • 3 years ago
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    i have to go now but i 'll try it

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