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maddiemaze

  • 3 years ago

Use substitution to solve the system. x=2y+8 2x-3y=13

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  1. dmezzullo
    • 3 years ago
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    erm, multiply the first equation by \(-2\). that yields\[\begin{cases}-2x = -4y - 16 \\ 2x - 3y = 13\end{cases}\]add both equations and solve for \(y\).

  2. johnweldon1993
    • 3 years ago
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    you already know what x equals...so sub it in for x in the second equation 2(2y+8) - 3y = 13 Now just distribute and simplify

  3. johnweldon1993
    • 3 years ago
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    dmezz thats elimination ...the problem asked for substitution :)

  4. newr3d
    • 3 years ago
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    solve each system by the elimination method 1)3x+2y=10 2x+y=7 2)3x-2y=7 2x-y=8 3)2x+3y=-13 -4x+6y=-10

  5. harsimran_hs4
    • 3 years ago
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    you already have the value of x from the first equation just substitute that value and get the answer

  6. dmezzullo
    • 3 years ago
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    ah, yes. my bad

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