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Use substitution to solve the system. x=2y+8 2x-3y=13

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erm, multiply the first equation by \(-2\). that yields\[\begin{cases}-2x = -4y - 16 \\ 2x - 3y = 13\end{cases}\]add both equations and solve for \(y\).
you already know what x sub it in for x in the second equation 2(2y+8) - 3y = 13 Now just distribute and simplify
dmezz thats elimination ...the problem asked for substitution :)

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solve each system by the elimination method 1)3x+2y=10 2x+y=7 2)3x-2y=7 2x-y=8 3)2x+3y=-13 -4x+6y=-10
you already have the value of x from the first equation just substitute that value and get the answer
ah, yes. my bad

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