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Please Help With Factoring. 81m^4 + 72m^2n +16n^2

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Can Youu Explain Please.?
\[(9m ^{2}+4n)^{2}\]
Still Not Understanding...

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Other answers:

\[(a + b)^{2} = a ^{2} + 2ab + b ^{2}\]
compare your expression with the one that jeevan posted
a^2 = 81m^4 so a = 9m^2 now do the same with b^2 = 16n^2
I Really Need An Explanation, Step To Step.
can you see what b = ?
having found b you substitute the values you ve found for a and b into (a + b)^2
You must figure out numbers that will work. Numbers that when multiplied = 16
Will The Answer Be 9m^2+8n)^2
no 8 times 8 is not 16
b^2 = 16n^2 take square root of both sides: b = 4n
81m^(4)+72m^(2)*n+16n^(2) 81m^(4)+72m^(2)n+16n^(2) (9m^(2)+4n)(9m^(2)+4n) (9m^(2)+4n)^(2)
Okay I Think I Get It.
Thank Youu.

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