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miraclelovesyouu

Please Help With Factoring. 81m^4 + 72m^2n +16n^2

  • one year ago
  • one year ago

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  1. miraclelovesyouu
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    Can Youu Explain Please.?

    • one year ago
  2. Kanwar245
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    \[(9m ^{2}+4n)^{2}\]

    • one year ago
  3. miraclelovesyouu
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    Still Not Understanding...

    • one year ago
  4. jeevan.sukh
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    \[(a + b)^{2} = a ^{2} + 2ab + b ^{2}\]

    • one year ago
  5. cwrw238
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    compare your expression with the one that jeevan posted

    • one year ago
  6. cwrw238
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    a^2 = 81m^4 so a = 9m^2 now do the same with b^2 = 16n^2

    • one year ago
  7. miraclelovesyouu
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    I Really Need An Explanation, Step To Step.

    • one year ago
  8. cwrw238
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    can you see what b = ?

    • one year ago
  9. miraclelovesyouu
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    No.

    • one year ago
  10. cwrw238
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    having found b you substitute the values you ve found for a and b into (a + b)^2

    • one year ago
  11. Mertsj
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    |dw:1362787677310:dw|

    • one year ago
  12. Mertsj
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    You must figure out numbers that will work. Numbers that when multiplied = 16

    • one year ago
  13. miraclelovesyouu
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    Will The Answer Be 9m^2+8n)^2

    • one year ago
  14. Mertsj
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    no 8 times 8 is not 16

    • one year ago
  15. cwrw238
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    b^2 = 16n^2 take square root of both sides: b = 4n

    • one year ago
  16. Luis_Rivera
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    81m^(4)+72m^(2)*n+16n^(2) 81m^(4)+72m^(2)n+16n^(2) (9m^(2)+4n)(9m^(2)+4n) (9m^(2)+4n)^(2)

    • one year ago
  17. miraclelovesyouu
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    Okay I Think I Get It.

    • one year ago
  18. cwrw238
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    good

    • one year ago
  19. miraclelovesyouu
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    Thank Youu.

    • one year ago
  20. cwrw238
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    welcome

    • one year ago
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