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miraclelovesyouu

  • 3 years ago

Please Help With Factoring. 81m^4 + 72m^2n +16n^2

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  1. miraclelovesyouu
    • 3 years ago
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    Can Youu Explain Please.?

  2. Kanwar245
    • 3 years ago
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    \[(9m ^{2}+4n)^{2}\]

  3. miraclelovesyouu
    • 3 years ago
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    Still Not Understanding...

  4. jeevan.sukh
    • 3 years ago
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    \[(a + b)^{2} = a ^{2} + 2ab + b ^{2}\]

  5. cwrw238
    • 3 years ago
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    compare your expression with the one that jeevan posted

  6. cwrw238
    • 3 years ago
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    a^2 = 81m^4 so a = 9m^2 now do the same with b^2 = 16n^2

  7. miraclelovesyouu
    • 3 years ago
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    I Really Need An Explanation, Step To Step.

  8. cwrw238
    • 3 years ago
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    can you see what b = ?

  9. miraclelovesyouu
    • 3 years ago
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    No.

  10. cwrw238
    • 3 years ago
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    having found b you substitute the values you ve found for a and b into (a + b)^2

  11. Mertsj
    • 3 years ago
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    |dw:1362787677310:dw|

  12. Mertsj
    • 3 years ago
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    You must figure out numbers that will work. Numbers that when multiplied = 16

  13. miraclelovesyouu
    • 3 years ago
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    Will The Answer Be 9m^2+8n)^2

  14. Mertsj
    • 3 years ago
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    no 8 times 8 is not 16

  15. cwrw238
    • 3 years ago
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    b^2 = 16n^2 take square root of both sides: b = 4n

  16. Luis_Rivera
    • 3 years ago
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    81m^(4)+72m^(2)*n+16n^(2) 81m^(4)+72m^(2)n+16n^(2) (9m^(2)+4n)(9m^(2)+4n) (9m^(2)+4n)^(2)

  17. miraclelovesyouu
    • 3 years ago
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    Okay I Think I Get It.

  18. cwrw238
    • 3 years ago
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    good

  19. miraclelovesyouu
    • 3 years ago
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    Thank Youu.

  20. cwrw238
    • 3 years ago
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    welcome

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