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zepdrixBest ResponseYou've already chosen the best response.1
dw:1362772905106:dwUnderstand why I drew that triangle in the third quadrant?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362773055192:dw They told us that the angle t in within this interval.\(\large \pi<t<3\pi/2\). So we draw a line in the third quadrant and form a triangle from it.
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
ok now i understand that part
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362773145892:dwLet's look at just the triangle now. Don't worry about the fact that I labeled the angle \(\large t'\). That's not super important. Just think of it as \(\large t\).
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\(\large \cos t=\dfrac{1}{5}=\dfrac{adjacent}{hypotenuse}\) So how would we label these sides? HINT: We always let the hypotenuse be positive.
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
dw:1362773386830:dw
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Ok looks good! Just need to find the missing side using the `Pythagorean Theorem` and then we just have one small step after that.
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
opposite will equal 4?
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
sorry did an error......missing side equals to \[+/ 2\sqrt{6}\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Ok looks good. Now remember that we drew our triangle in the `third` quadrant. So for that OPPOSITE leg, did we move UP or DOWN? Do we want the positive or negative answer?
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
we want a negative answer because tan is only positive in the 3rd Q
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Haha that's an interesting way to think about it XD I was thinking about the fact that we moved downward in the y direction to make the opposite length. So it would be negative. But whatever works for you! :Ddw:1362773803586:dw
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Ok good. Everything is labeled correctly. Just have to find \(\large \csc t\) now! :)
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
hypotenuse over opposite
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
For your final answer it might be a good idea to `rationalize` your answer. Get the irrational number out of the denominator. Multiply the top and bottom by sqrt6.
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
a little confused on the denominator part....not sure if its 12 or not
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large 2 \cdot \sqrt6 \sqrt6 \qquad = \qquad 2\cdot6 \qquad = \qquad 12\]Hmm yah everything looks ok there!
 one year ago

mattlai7Best ResponseYou've already chosen the best response.0
thanks for the help some time a 8am class only aborbs so much in an hour and with 300 classmates lol
 one year ago
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