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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1362772905106:dwUnderstand why I drew that triangle in the third quadrant?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1362773055192:dw They told us that the angle t in within this interval.\(\large \pi<t<3\pi/2\). So we draw a line in the third quadrant and form a triangle from it.

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0ok now i understand that part

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1362773145892:dwLet's look at just the triangle now. Don't worry about the fact that I labeled the angle \(\large t'\). That's not super important. Just think of it as \(\large t\).

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \cos t=\dfrac{1}{5}=\dfrac{adjacent}{hypotenuse}\) So how would we label these sides? HINT: We always let the hypotenuse be positive.

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362773386830:dw

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok looks good! Just need to find the missing side using the `Pythagorean Theorem` and then we just have one small step after that.

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0opposite will equal 4?

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0sorry did an error......missing side equals to \[+/ 2\sqrt{6}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok looks good. Now remember that we drew our triangle in the `third` quadrant. So for that OPPOSITE leg, did we move UP or DOWN? Do we want the positive or negative answer?

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0we want a negative answer because tan is only positive in the 3rd Q

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Haha that's an interesting way to think about it XD I was thinking about the fact that we moved downward in the y direction to make the opposite length. So it would be negative. But whatever works for you! :Ddw:1362773803586:dw

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok good. Everything is labeled correctly. Just have to find \(\large \csc t\) now! :)

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0hypotenuse over opposite

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1For your final answer it might be a good idea to `rationalize` your answer. Get the irrational number out of the denominator. Multiply the top and bottom by sqrt6.

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0a little confused on the denominator part....not sure if its 12 or not

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large 2 \cdot \sqrt6 \sqrt6 \qquad = \qquad 2\cdot6 \qquad = \qquad 12\]Hmm yah everything looks ok there!

mattlai7
 one year ago
Best ResponseYou've already chosen the best response.0thanks for the help some time a 8am class only aborbs so much in an hour and with 300 classmates lol
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