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|dw:1362772905106:dw|Understand why I drew that triangle in the third quadrant?

not quite sure why?

|dw:1362773055192:dw| They told us that the angle t in within this interval.\(\large \pi

ok now i understand that part

|dw:1362773386830:dw|

opposite will equal 4?

sorry did an error......missing side equals to \[+/- 2\sqrt{6}\]

we want a negative answer because tan is only positive in the 3rd Q

Ok good. Everything is labeled correctly. Just have to find \(\large \csc t\) now! :)

hypotenuse over opposite

yepppppp

5/-2sqrt6

yay good job! \c:/

5sqrt6/-12?

Yes.

a little confused on the denominator part....not sure if its 12 or not

ok thanks!!!

thanks for the help some time a 8am class only aborbs so much in an hour and with 300 classmates lol

heh ill bet! XD