Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

onegirlBest ResponseYou've already chosen the best response.0
@zepdrix i ddi it but can u check my answer?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
sure :O what are you suppose to do? Just find the derivative then plug \(\large a\) in? Or does this have something to do with approximation?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
okay my teacher said there is an equation, so here is what i did f(x) = cos (x) f'(x) = sin(x) x = a = pi/2 so f'(pi/2) = sin (pi/2) = 1
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Your teacher said there is an equation? :) That's not much detail lolol Your derivative looks correct at least.
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
yea she said try again there is an equation
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
let me show you how i wrote it first okay?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
i mean the answer i wrote first
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
d/dx ( cos (x)) = sin(x) sin (pi/2) = 1, so the slope is 1, y = mx + b > y = =1x + b cos (pi/2) = 0 so the coordinates pare are (pi/2, 0) so y = 0x + b, 0(pi/2) + b equals to 0, 0 = y = 0x + 0 = y = 0 for my final answer.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Oh so like the previous problems, you're looking for an equation of the tangent line?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
yes sorry i made a mistake
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
yes yes the equation of the tangent line
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large y=x+b\] From here you plugged in your point \(\large \left(\pi/2,\;0\right)\). \[\large 0=\pi/2+b \qquad \qquad \rightarrow \qquad \qquad b=\pi/2\] I think you plugged your \(\large 0\) into the wrong spot.
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so instead of 0 = 0(pi/2) + b what would i write
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\huge (\color{royalblue}{\pi/2},\;\color{orangered}{0}) \qquad = \qquad (\color{royalblue}{x},\;\color{orangered}{y})\] Plug them into here, match up the colors.\[\huge \color{orangered}{y}=(1)\color{royalblue}{x}+b\] I'm not sure why you're plugging a \(\large 0\) in for your 1....
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so 0 = (1)(pi/2) + b ?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.