At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

do u know the general form?

yes, y=a(x-h)^2+k

did u need it in linear form?

like the general form of a linear equation?

just the general form of a quadratic equation

okay, so u need to know the quadratic formula i believe..do u know it?

general form> y=a(x-h)^2+k

oh, yeah!

quadratic formula> -b+-sqrt(b-4(a)(c))/2(a)

but how does that help convert it to general form?

I thought it just helped find the x-intercepts..

I know how to convert it... the problem is the 2 in 2x^2

General form of what?

quadratic equations

thanks (:

\[y=2x^2+6x+4\]
\[y=2(x^2+3x+______ )+4\]

Now factor:
\[y=2(x+\frac{3}{2})^2-\frac{1}{2}\]

why 3/2?

I want to show you something:
\[x^2+6x+9=(x+3)^2\]

\[x^2+8x+16=(x+4)^2\]

I don't get what you did with: (3/2^2)+4−92

Notice the relationship between the coefficient of x and the constant term in a trinomial square.

If you take 1/2 the coefficient and square it, you get the constant term.

Follow me?

I think so

The relationship between the coefficient of x and the constant term.

oh, that half of the coefficient of x to the second power = the constant. okay, cool

Thank you for helping me (:

yw