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that1chick
 2 years ago
how do you write y = 2x2 + 6x + 4 in general form?
that1chick
 2 years ago
how do you write y = 2x2 + 6x + 4 in general form?

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iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0do u know the general form?

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0did u need it in linear form?

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0like the general form of a linear equation?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0just the general form of a quadratic equation

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0okay, so u need to know the quadratic formula i believe..do u know it?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0general form> y=a(xh)^2+k

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0quadratic formula> b+sqrt(b4(a)(c))/2(a)

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0but how does that help convert it to general form?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0I thought it just helped find the xintercepts..

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0if i can remember this correctly, i believe u need to first solve to get the values of a,b,c and then you just plug it into the general form... I'm not 100% sure tho... @abb0t, am i remembering this correctly? ;/

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0I know how to convert it... the problem is the 2 in 2x^2

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.02 in 2x^2 is the problem.... you isolate the x variables getting: y4=2x^2+6x then complete the square and balance the equation: 6/2=3 3^2=9, y4+9=2x^2+6x+9, y+5=2x^2+6x+9 then convert the trinomial into a binomial... thus lies my dilemma

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0sorry, i'm not very sure, cuz i don't think i remember this correctly ahha and i don't wanna help u wrongly haha @Mertsj probs knows :) good luck!!! :D

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2\[y=2x^2+6x+4\] \[y=2(x^2+3x+______ )+4\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Now complete the square by adding (3/2)^2 inside the parentheses: \[y=2(x^2+3x+(\frac{3}{2})^2)+4\frac{9}{2}\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Now factor: \[y=2(x+\frac{3}{2})^2\frac{1}{2}\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2I want to show you something: \[x^2+6x+9=(x+3)^2\]

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0I don't get what you did with: (3/2^2)+4−92

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Notice the relationship between the coefficient of x and the constant term in a trinomial square.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2If you take 1/2 the coefficient and square it, you get the constant term.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2So I took 1/2 of 3 and got 3/2. Then I squared it and added it to the x^2 + 3x to get a trinomial square.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2Now the (3/2)^2 was inside a parenthesis which has a 2 in front of it so I was really adding 2 times (3/2)^2 which is 2 times 9/4 which is 9/2. So since I could not change the equation, I then had to subtract 9/2.

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, yes! I get what you did (: thank you! what were you trying to show me with those other two equations?

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.2The relationship between the coefficient of x and the constant term.

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0oh, that half of the coefficient of x to the second power = the constant. okay, cool

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you for helping me (:
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