Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

how do you write y = 2x2 + 6x + 4 in general form?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

do u know the general form?
yes, y=a(x-h)^2+k
did u need it in linear form?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

like the general form of a linear equation?
just the general form of a quadratic equation
okay, so u need to know the quadratic formula i u know it?
general form> y=a(x-h)^2+k
oh, yeah!
quadratic formula> -b+-sqrt(b-4(a)(c))/2(a)
but how does that help convert it to general form?
I thought it just helped find the x-intercepts..
if i can remember this correctly, i believe u need to first solve to get the values of a,b,c and then you just plug it into the general form... I'm not 100% sure tho... @abb0t, am i remembering this correctly? ;/
I know how to convert it... the problem is the 2 in 2x^2
General form of what?
quadratic equations
2 in 2x^2 is the problem.... you isolate the x variables getting: y-4=2x^2+6x then complete the square and balance the equation: 6/2=3 3^2=9, y-4+9=2x^2+6x+9, y+5=2x^2+6x+9 then convert the trinomial into a binomial... thus lies my dilemma
sorry, i'm not very sure, cuz i don't think i remember this correctly ahha and i don't wanna help u wrongly haha @Mertsj probs knows :) good luck!!! :D
thanks (:
\[y=2x^2+6x+4\] \[y=2(x^2+3x+______ )+4\]
Now complete the square by adding (3/2)^2 inside the parentheses: \[y=2(x^2+3x+(\frac{3}{2})^2)+4-\frac{9}{2}\]
Now factor: \[y=2(x+\frac{3}{2})^2-\frac{1}{2}\]
why 3/2?
I want to show you something: \[x^2+6x+9=(x+3)^2\]
I don't get what you did with: (3/2^2)+4−92
Notice the relationship between the coefficient of x and the constant term in a trinomial square.
If you take 1/2 the coefficient and square it, you get the constant term.
So I took 1/2 of 3 and got 3/2. Then I squared it and added it to the x^2 + 3x to get a trinomial square.
Now the (3/2)^2 was inside a parenthesis which has a 2 in front of it so I was really adding 2 times (3/2)^2 which is 2 times 9/4 which is 9/2. So since I could not change the equation, I then had to subtract 9/2.
Follow me?
I think so
Okay, yes! I get what you did (: thank you! what were you trying to show me with those other two equations?
The relationship between the coefficient of x and the constant term.
oh, that half of the coefficient of x to the second power = the constant. okay, cool
Thank you for helping me (:

Not the answer you are looking for?

Search for more explanations.

Ask your own question