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lovesit2xBest ResponseYou've already chosen the best response.0
\[Find dr/d \theta. r=\sin (42\theta)\]
 one year ago

ravinaBest ResponseYou've already chosen the best response.0
ambra te paundi hai udariyan
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Hmm so what would the derivative of \(\large \sin\theta\) be? This is another one of those problems where we'll have to work with the chain rule. :)
 one year ago

ravinaBest ResponseYou've already chosen the best response.0
phul koi vilayti ala lae gaya udd main reh gaya kyarian
 one year ago

mathsmindBest ResponseYou've already chosen the best response.0
ur previous question was solved @lovesit2x
 one year ago

lovesit2xBest ResponseYou've already chosen the best response.0
yes it was, thanks for your help @mathsmind
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Yes good! Since the inside of the sine is more than just \(\large \theta\), we have to apply the chain rule, multiplying by the derivative of the inside. \[\huge r'=\cos(42\theta)\color{royalblue}{\left(42\theta\right)'}\]
 one year ago

lovesit2xBest ResponseYou've already chosen the best response.0
cos(42theta) (2) ?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Understand the process? We took the derivative of sine, which gave us cosine (with the same contents inside of it). And then we make a copy of the inside, and multiply by it's derivative.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\huge r'=2\cos(42\theta)\]Yay!
 one year ago
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