## anonymous 3 years ago r=sin(4-2theta)

1. anonymous

$Find dr/d \theta. r=\sin (4-2\theta)$

2. anonymous

@zepdrix

3. anonymous

ambra te paundi hai udariyan

4. zepdrix

Hmm so what would the derivative of $$\large \sin\theta$$ be? This is another one of those problems where we'll have to work with the chain rule. :)

5. anonymous

phul koi vilayti ala lae gaya udd main reh gaya kyarian

6. anonymous

cos theta

7. anonymous

ur previous question was solved @lovesit2x

8. anonymous

ho attiye kapurthaliye

9. anonymous

yes it was, thanks for your help @mathsmind

10. zepdrix

Yes good! Since the inside of the sine is more than just $$\large \theta$$, we have to apply the chain rule, multiplying by the derivative of the inside. $\huge r'=\cos(4-2\theta)\color{royalblue}{\left(4-2\theta\right)'}$

11. anonymous

cos(4-2theta) (-2) ?

12. zepdrix

Understand the process? We took the derivative of sine, which gave us cosine (with the same contents inside of it). And then we make a copy of the inside, and multiply by it's derivative.

13. zepdrix

Yah sounds good!

14. anonymous

:D yay!!

15. zepdrix

$\huge r'=-2\cos(4-2\theta)$Yay!