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lovesit2x

  • 3 years ago

y=sin(sin(x)) find the derivative

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  1. wio
    • 3 years ago
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    Use the chain rule.

  2. malcolm11235
    • 3 years ago
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    Or gogle wolfram alpha derivative calculator if your unsure of your answer

  3. lovesit2x
    • 3 years ago
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    cos^2x?

  4. sami-21
    • 3 years ago
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    \[\Large y'=\cos(\sin(x))*\frac{d}{dx}(\sin(x)=\cos(\sin(x))*\cos(x)\]

  5. lovesit2x
    • 3 years ago
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    thanks

  6. stamp
    • 3 years ago
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    \[y=sin(sin(x))\]\[u=sin(x)\]\[du/dx=cos(x)\]substitute sin(x) = u\[y=sin(u)\]take the derivitive; recall the chain rule\[dy/dx=cos(u)du/dx\]\[y'=cos(u)cos(x)\]substitute u = sin(x) back\[y'=cos(sin(x))cos(x)\] verification - http://www.wolframalpha.com/input/?i=derivative+of+sin%28sin%28x%29%29

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