Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
ksaimouli
Group Title
From 5 employees at a company, a group of 3 employees will
be chosen to work on a project. How many different groups
of 3 employees can be chosen?
 one year ago
 one year ago
ksaimouli Group Title
From 5 employees at a company, a group of 3 employees will be chosen to work on a project. How many different groups of 3 employees can be chosen?
 one year ago
 one year ago

This Question is Closed

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
is their any easy technique it is hard to do mentally
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
what i do is (3)(3) because 3 people only once
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
So this is probability stuff right? Since `order` doesn't matter this is a Combination problem, not a Permutation. Understand what I mean by "order doesn't matter"? If Bob, Suzy and then Tom get picked. That's the same as Suzy, Tom and then Bob getting picked. The order they were picked in doesn't matter. The notation can be written like this, \(\large _5C_3\) Which would be read, "5 choose 3". \[\large _nC_r \qquad = \qquad \frac{n!}{r!(nr)!}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
(3)(3)? Hmm maybe there is a simple way to do this like by building a tree, and such. But I'm not really comfortable with this subject of material to explain it that way :\ heh
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yah that sounds right c:
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.