geerky42
\[\Large \int \dfrac{dx}{\ln x}\]
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inkyvoyd
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set u=ln x then du/dx/u
inkyvoyd
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you should be able to figure it out with u-sub
geerky42
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du/dx/u?
geerky42
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but then how can I use du? There is no place to put du
inkyvoyd
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I may have overlooked this >.< gimme a minute getting some paper
Kanwar245
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Integration by parts?
Xavier
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It can't be expressed in terms of other functions.
That integral is the basis of the logarithmic integral function \[li(x)=\int_{0}^{x}\frac{dt}{ln(t)}\]
Kanwar245
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u = 1/ln x, dv = 1
inkyvoyd
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No, I'm correct.
inkyvoyd
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u=lnx
du=dx/u
Int 1/u dx=int du
geerky42
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Please explain more clear @inkyvoyd How to use u-substitution?
inkyvoyd
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int du=u
inkyvoyd
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gimme a minute lemme use latex
geerky42
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well then i get u = u it dont do anything.
geerky42
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I think @Xavier is correct, it can't be expressed
inkyvoyd
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yes, xavier is in fact correct (facepalm)
geerky42
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Thank you, here's gif
inkyvoyd
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LOL