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geerky42

\[\Large \int \dfrac{dx}{\ln x}\]

  • one year ago
  • one year ago

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  1. inkyvoyd
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    set u=ln x then du/dx/u

    • one year ago
  2. inkyvoyd
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    you should be able to figure it out with u-sub

    • one year ago
  3. geerky42
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    du/dx/u?

    • one year ago
  4. geerky42
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    but then how can I use du? There is no place to put du

    • one year ago
  5. inkyvoyd
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    I may have overlooked this >.< gimme a minute getting some paper

    • one year ago
  6. Kanwar245
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    Integration by parts?

    • one year ago
  7. Xavier
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    It can't be expressed in terms of other functions. That integral is the basis of the logarithmic integral function \[li(x)=\int_{0}^{x}\frac{dt}{ln(t)}\]

    • one year ago
  8. Kanwar245
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    u = 1/ln x, dv = 1

    • one year ago
  9. inkyvoyd
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    No, I'm correct.

    • one year ago
  10. inkyvoyd
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    u=lnx du=dx/u Int 1/u dx=int du

    • one year ago
  11. geerky42
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    Please explain more clear @inkyvoyd How to use u-substitution?

    • one year ago
  12. inkyvoyd
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    int du=u

    • one year ago
  13. inkyvoyd
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    gimme a minute lemme use latex

    • one year ago
  14. geerky42
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    well then i get u = u it dont do anything.

    • one year ago
  15. geerky42
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    I think @Xavier is correct, it can't be expressed

    • one year ago
  16. inkyvoyd
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    yes, xavier is in fact correct (facepalm)

    • one year ago
  17. inkyvoyd
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    http://www.wolframalpha.com/input/?i=integrate+1%2Fln+x

    • one year ago
  18. geerky42
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    Thank you, here's gif

    • one year ago
  19. inkyvoyd
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    LOL

    • one year ago
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