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mrbrian
with this derivative -(y/x)^(1/3) find the equation of the tangent line at point (1/8, (3(3)^(1/3))/8).
the textbook says it is 2(3)^(1/3) + 2y - 3^(1/3) = 0 i cant figure out how they got that
my result is 8x(3(3)^(1/3) + 8y - (3(3)^(1/3)) - 3(3)^(1/3) = 0.. how do i simplify it further?
I am not sure what you are trying to write. Try drawing the equations with your mouse, or use the equation editor.