anonymous
  • anonymous
with this derivative -(y/x)^(1/3) find the equation of the tangent line at point (1/8, (3(3)^(1/3))/8).
Calculus1
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
the textbook says it is 2(3)^(1/3) + 2y - 3^(1/3) = 0 i cant figure out how they got that
anonymous
  • anonymous
my result is 8x(3(3)^(1/3) + 8y - (3(3)^(1/3)) - 3(3)^(1/3) = 0.. how do i simplify it further?
stamp
  • stamp
I am not sure what you are trying to write. Try drawing the equations with your mouse, or use the equation editor.

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