## lvasquev462 2 years ago Algebra 1 Questions

1. lvasquev462

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2. johnweldon1993

so you add 4 to both sides....now you have x/3 = 15 multiply both sides by 3 which leave x = 45 now check....45/3? is 15...- 4 = 11 so yes

3. lvasquev462

I have 10 more questions is that ok

4. johnweldon1993

Yeah sure....I'm about to sign off inna few mins but anyone else can see this so they'll be able to help

5. lvasquev462

k

6. lvasquev462

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7. johnweldon1993

Okay so combine like terms 2x - 4x = -2x 1 - 9 = -8 so we have -2x - 8 =12 now add 8 to both sides -2x = 20 x = -10

8. lvasquev462

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9. lvasquev462

will it be 8x-6

10. kropot72

@@lvasquev462 Do you want me to help you through the method of solution?

11. lvasquev462

12. kropot72

3(x - 3) = 5(x + 3) First remove the brackets on each side by multiplying each term inside the brackets by the term outside the brackets. Can you do that?

13. lvasquev462

yes 3x- 9 = 5x - 15

14. lvasquev462

+15 i mean

15. kropot72

Good work! So now we have: 3x - 9 = 5x + 15 Now subtract 3x from both sides. Can you do that?

16. lvasquev462

luhm i get lost right here can u help me please

17. kropot72

What is the result of subtracting 3x from 3x; 3x - 3x = ?

18. lvasquev462

0 ?

19. kropot72

Correct! So now when we subtract 3x from both sides of 3x - 9 = 5x + 15 we get -9 = 5x - 3x + 15 What happens to the right hand side when you combine the two terms in x?

20. kropot72

5x - 3x = ?x

21. lvasquev462

2x right

22. lvasquev462

i got 17 = x if i skip ahead will tht be correct

23. kropot72

Correct again! Our equation has now become -9 = 2x + 15 Next step is to subtract 15 from both sides to get the term in x all by itself on the right hand side. Can you do that?

24. lvasquev462

-12

25. kropot72

Sorry x = 17 is not correct. Please continue with the method I am showing you :)

26. lvasquev462

15 minus 9 is -24

27. kropot72

Well -15 - 9 = -24 sure enough. So we have -24 = 2x And x = -24/2 = ?

28. lvasquev462

-12

29. kropot72

Correct. The solution is x = -12.

30. lvasquev462

thanks dude i appreciate your help