a bag contains 3white and 4red balls.two draws of one ball each are made without replacement.what is the probability that one is red and other is white

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- RadEn

Probability one is red of the first draw is 4/7
Probability one is white of the 2nd draw is 3/6 =1/2
multiply of both up, we get 4/7 * 1/2 = 4/14 = 2/7

- RadEn

does that make sense, @pooja123 ?

- anonymous

the answer is 4/7.

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## More answers

- RadEn

4/7 is just for the probalility of one red only :)
do u want draw 2 balls, right ?

- anonymous

yes they used the formula like 2into4into3/7into 6

- RadEn

hmm. i dont understand that, actually the formula to get the probability of an event using : P(A) = number of event A / number all event

- nubeer

hmm well she is right the answer would be 4/7

- RadEn

why, can u explain more, nubber ?

- nubeer

we found the probability 2/7 when first red and second white
so P[RW] = 2/7
this is one case another possibility is that first is white and second is red
P[WR] = 3/7 * 4/6 = 2/7
so total probability of this event = p[WR]+p[RW]

- anonymous

thanks

- RadEn

wait, is draw it one by one Or 2 balls direct ?

- nubeer

hmm i think one by one...

- nubeer

glad to help :)

- anonymous

thank u guys

- RadEn

im not becareful with this question :)

- anonymous

k

- anonymous

can u see my isosceles triangle solution for one sec

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