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boomerang285

  • 2 years ago

Please help... Determine the measure of side c, given: a=3m b=4m B=41deg

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  1. AravindG
    • 2 years ago
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    tried cosine rule ?

  2. boomerang285
    • 2 years ago
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    im not sure how to do this at all....

  3. AravindG
    • 2 years ago
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    do u knw cosine rule ?

  4. boomerang285
    • 2 years ago
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    i have just started learning about it

  5. AravindG
    • 2 years ago
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    ok \[\cos B=\dfrac{a^2+c^2-b^2}{2ac} \]

  6. AravindG
    • 2 years ago
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    now solve for b

  7. t_soulb
    • 2 years ago
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    yea good cosine rule,,my answer is b=2.44 (approx.)

  8. dan815
    • 2 years ago
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    u could use sin law too i think

  9. t_soulb
    • 2 years ago
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    sorry 1.22

  10. AravindG
    • 2 years ago
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    @dan815 sin law wont work cause we need two angles :/

  11. dan815
    • 2 years ago
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    sin <b/b=sin<a=a sin<(180-(a+b))/c and solve for C

  12. dan815
    • 2 years ago
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    use my equation < means angle

  13. boomerang285
    • 2 years ago
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    actually my options are: 1.6m 4.5m 0.1m 5.7m I thought it was 1.6m?

  14. boomerang285
    • 2 years ago
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    am I wrong?

  15. boomerang285
    • 2 years ago
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    actually it was 5.7 after I figured it out.. Thanks though

  16. dan815
    • 2 years ago
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    did u use my formula!

  17. t_soulb
    • 2 years ago
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    yea approx.

  18. boomerang285
    • 2 years ago
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    yes thank you

  19. dan815
    • 2 years ago
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    np :)

  20. dan815
    • 2 years ago
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    if u remember that you need atleast 3 pieces of information to solve a triangle and that if the angle given is the angle of the opposite side then you can always use sin law if they give u like side a and b but give you angle C then you have to use cos law if its not a right angle triangle

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