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anonymous
 3 years ago
Solve 4x^2+8x–252=0 by graphing
anonymous
 3 years ago
Solve 4x^2+8x–252=0 by graphing

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tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1You should draw the graph. x = 0 corresponds to y = 252 Do more!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04x^2+8x–252=0> 0=4(x+1)^2256 Vertex x+1=0, x=1 Axis of symmetry 1 Domain All real numbers Range y>=4 Right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oops, forgot to finish the vertex... Vertex x+1=0, x=1 y=4(1+1)^2256 y=4(0)^2256 y=4(0)256 y=256 (1,256)

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1That's pretty good. There are a couple of refinements. 1) The Axis of Symmetry should be expressed as an equation of a line. x = 1 2) The Range is no good. For a parabola, this would always be a reference to the vertex. y >= 256
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