anonymous
  • anonymous
Solve 4x^2+8x–252=0 by graphing
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

tkhunny
  • tkhunny
You should draw the graph. x = 0 corresponds to y = -252 Do more!
anonymous
  • anonymous
4x^2+8x–252=0-> 0=4(x+1)^2-256 Vertex- x+1=0, x=-1 Axis of symmetry- -1 Domain- All real numbers Range- y>=4 Right?
anonymous
  • anonymous
Oops, forgot to finish the vertex... Vertex- x+1=0, x=-1 y=4(-1+1)^2-256 y=4(0)^2-256 y=4(0)-256 y=-256 (-1,-256)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

tkhunny
  • tkhunny
That's pretty good. There are a couple of refinements. 1) The Axis of Symmetry should be expressed as an equation of a line. x = -1 2) The Range is no good. For a parabola, this would always be a reference to the vertex. y >= -256
anonymous
  • anonymous
Thank you (:

Looking for something else?

Not the answer you are looking for? Search for more explanations.