A community for students.
Here's the question you clicked on:
 0 viewing
that1chick
 2 years ago
Solve 4x^2+8x–252=0 by graphing
that1chick
 2 years ago
Solve 4x^2+8x–252=0 by graphing

This Question is Closed

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1You should draw the graph. x = 0 corresponds to y = 252 Do more!

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.04x^2+8x–252=0> 0=4(x+1)^2256 Vertex x+1=0, x=1 Axis of symmetry 1 Domain All real numbers Range y>=4 Right?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.0Oops, forgot to finish the vertex... Vertex x+1=0, x=1 y=4(1+1)^2256 y=4(0)^2256 y=4(0)256 y=256 (1,256)

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1That's pretty good. There are a couple of refinements. 1) The Axis of Symmetry should be expressed as an equation of a line. x = 1 2) The Range is no good. For a parabola, this would always be a reference to the vertex. y >= 256
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.