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dan815Best ResponseYou've already chosen the best response.0
why dont you substitute those numbers into the formula and solve it
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Divide by \(\pi r^{2}\). \(\left(\pi r^{2}\right)\) is attached to 'h' via multiplication. Detach it via division.
 one year ago

christine87Best ResponseYou've already chosen the best response.0
@dan815 i clearly have done so already, but not coming up with the 'correct' answer according to the rest of the problem i'm inserting it into, hence why I'm seeing if im doing it wrong.
 one year ago

christine87Best ResponseYou've already chosen the best response.0
@tkhunny hi ther, thanks, but i'm not trying to solvefor h, i'm subsituting the numbers i posted above. . . seem to be coming up incorrect according to the book/problem set
 one year ago

dan815Best ResponseYou've already chosen the best response.0
what is the object you are trying to find the integral of?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
?? "Solve V = π r2h for h" Perhaps we're speaking a different language? One might ask, why are nyou not trying to solve for h? Are you studying Significant Figures"? What answer are you giving that is being rejected?
 one year ago

bradelyBest ResponseYou've already chosen the best response.0
step by step answers posted here http://www.mathskey.com/question2answer/2063/solvev%CF%80r2hforh ask your Algebra1 homework questions athttp://www.mathskey.com/question2answer/algebra1 and get free math help. all the best
 one year ago

christine87Best ResponseYou've already chosen the best response.0
its a beaker filled with a certain amount of liquid, all a part of a stream of different question s built off this one
 one year ago

christine87Best ResponseYou've already chosen the best response.0
@tkhunny because i HAVE h already, as posted above, im trying to find V
 one year ago

christine87Best ResponseYou've already chosen the best response.0
this is the complete problem : 5. Calculate the volume of the 50mL graduated cylinder using your measurements of diameter and height, using the formula V = ∏ r2h (r=½ diameter). This is your experimental value. Assuming the accepted value of the volume of the graduated cylinder is 50.00 mL, calculate the percent error of your volume calculation, using the following formula: Percent Error = /accepted value  experimental value/x 100 accepted value
 one year ago

dan815Best ResponseYou've already chosen the best response.0
lets compare answers i get for r = 1.35 h = 12.7 pi*2*r*h = 107.725212092
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
That's okay, but I'm really curious how this is consistent with "Solve V = π r2h for h". Anyway, it appears we ARE studying Significant Figures. Now answer the question. What value are you using that is being rejected?
 one year ago

dan815Best ResponseYou've already chosen the best response.0
that is area tho i think you mean pi * r^2 *h = 72.7145181618
 one year ago

christine87Best ResponseYou've already chosen the best response.0
i'm getting 72.7145. . .but when i plug it into the next step in my problem it doesnt make any sense! im getting a negative percentage error
 one year ago

dan815Best ResponseYou've already chosen the best response.0
it says its pir2h so u shud use the other one 107.725212092
 one year ago

dan815Best ResponseYou've already chosen the best response.0
your question is wrong i think it shud say pir^2*2 not pi*r2h
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Well, a negative value isn't possible if you are using the absolute values. Are you using the absolute values? Also, 72.71415 is no good. Use 72.7
 one year ago

dan815Best ResponseYou've already chosen the best response.0
pi*r^2 *h dw:1362879713114:dw
 one year ago

christine87Best ResponseYou've already chosen the best response.0
im totally stumped this is the exact problem taken off the homework, nothing seems to fit
 one year ago

dan815Best ResponseYou've already chosen the best response.0
i will help you okay!! if you let me help you
 one year ago

christine87Best ResponseYou've already chosen the best response.0
@dan815 ok thank you. . .im given D = 2.7 and H = 12.7 and r is 1/2 of D
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Well, 72.7 mL is a rather horrible approximation for a 50.0 mL beaker. Maybe something else went wrong. Or, maybe we're just testing the %Errors formula. \(\dfrac{50.0  72.7}{50.00}\cdot 100\;=\;\dfrac{ 22.7}{50.00}\cdot 100\;=\;\)
 one year ago

dan815Best ResponseYou've already chosen the best response.0
ok your V = 1.35^2pi*12.7 = 72.7 (72.750/50)*100 = ansswer to 2 decimal places
 one year ago

christine87Best ResponseYou've already chosen the best response.0
its a negative number because its the accepted (50) minus the experiemental number, not the other way around thats why im not understanding
 one year ago

dan815Best ResponseYou've already chosen the best response.0
wuts a negative number?
 one year ago

dan815Best ResponseYou've already chosen the best response.0
is the percentage negative?
 one year ago

christine87Best ResponseYou've already chosen the best response.0
the result is negative
 one year ago

dan815Best ResponseYou've already chosen the best response.0
oh okay then its 45.43%
 one year ago

christine87Best ResponseYou've already chosen the best response.0
how is it possible to have a regative as an answer to this particular question tho?
 one year ago

dan815Best ResponseYou've already chosen the best response.0
its possible if its 've then it means ur value was 45.43% more than the actual value if its positive then its 45.43% less than the actual value
 one year ago

dan815Best ResponseYou've already chosen the best response.0
though i think your question should say do the absolute value of the percentage of error
 one year ago

dan815Best ResponseYou've already chosen the best response.0
but if they are defining the percentage of error without absolute value then u can get negative values
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
You are overlooking the Absolute Values. 50.0  72.7 = 72.7  50.0 = 22.7 There cannot be a negative value resulting from this operation.
 one year ago

christine87Best ResponseYou've already chosen the best response.0
ooohh ok i have no idea i havent been taught absolute values, just thrown this problem set today
 one year ago

dan815Best ResponseYou've already chosen the best response.0
those 2 lines around the numbers mean take the absolute value so whatever the value they are always take the positive of it
 one year ago

christine87Best ResponseYou've already chosen the best response.0
i was given this: Percent Error = /accepted value  experimental value/x 100 accepted value written exactly as it is, no boxes or lines around etc
 one year ago

dan815Best ResponseYou've already chosen the best response.0
the equation for absolute value is this dw:1362882330695:dw
 one year ago

dan815Best ResponseYou've already chosen the best response.0
always gives positive answer
 one year ago

dan815Best ResponseYou've already chosen the best response.0
those / / mean absolute value
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
What are those slanty lines? Those are supposed to be Absolute Value Symbols. Trust me on this.
 one year ago

dan815Best ResponseYou've already chosen the best response.0
i wish u were asian right now_
 one year ago
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