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christine87

  • one year ago

Solve V = π r2h for h. Show all work. Help?

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  1. godorovg
    • one year ago
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    welcome to openstudy

  2. christine87
    • one year ago
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    r = 1.35 h = 12.7

  3. dan815
    • one year ago
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    hi

  4. dan815
    • one year ago
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    why dont you substitute those numbers into the formula and solve it

  5. tkhunny
    • one year ago
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    Divide by \(\pi r^{2}\). \(\left(\pi r^{2}\right)\) is attached to 'h' via multiplication. Detach it via division.

  6. christine87
    • one year ago
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    @dan815 i clearly have done so already, but not coming up with the 'correct' answer according to the rest of the problem i'm inserting it into, hence why I'm seeing if im doing it wrong.

  7. christine87
    • one year ago
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    @tkhunny hi ther, thanks, but i'm not trying to solvefor h, i'm subsituting the numbers i posted above. . . seem to be coming up incorrect according to the book/problem set

  8. dan815
    • one year ago
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    what is the object you are trying to find the integral of?

  9. dan815
    • one year ago
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    volume of* sorry

  10. dan815
    • one year ago
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    is it a cylinder?

  11. tkhunny
    • one year ago
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    ?? "Solve V = π r2h for h" Perhaps we're speaking a different language? One might ask, why are nyou not trying to solve for h? Are you studying Significant Figures"? What answer are you giving that is being rejected?

  12. bradely
    • one year ago
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    step by step answers posted here http://www.mathskey.com/question2answer/2063/solve-v-%CF%80-r-2-h-for-h ask your Algebra1 homework questions athttp://www.mathskey.com/question2answer/algebra-1 and get free math help. all the best

  13. christine87
    • one year ago
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    its a beaker filled with a certain amount of liquid, all a part of a stream of different question s built off this one

  14. christine87
    • one year ago
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    @tkhunny because i HAVE h already, as posted above, im trying to find V

  15. christine87
    • one year ago
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    this is the complete problem : 5. Calculate the volume of the 50mL graduated cylinder using your measurements of diameter and height, using the formula V = ∏ r2h (r=½ diameter). This is your experimental value. Assuming the accepted value of the volume of the graduated cylinder is 50.00 mL, calculate the percent error of your volume calculation, using the following formula: Percent Error = /accepted value - experimental value/x 100 accepted value

  16. dan815
    • one year ago
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    lets compare answers i get for r = 1.35 h = 12.7 pi*2*r*h = 107.725212092

  17. tkhunny
    • one year ago
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    That's okay, but I'm really curious how this is consistent with "Solve V = π r2h for h". Anyway, it appears we ARE studying Significant Figures. Now answer the question. What value are you using that is being rejected?

  18. dan815
    • one year ago
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    that is area tho i think you mean pi * r^2 *h = 72.7145181618

  19. christine87
    • one year ago
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    i'm getting 72.7145. . .but when i plug it into the next step in my problem it doesnt make any sense! im getting a negative percentage error

  20. dan815
    • one year ago
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    it says its pir2h so u shud use the other one 107.725212092

  21. dan815
    • one year ago
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    your question is wrong i think it shud say pir^2*2 not pi*r2h

  22. tkhunny
    • one year ago
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    Well, a negative value isn't possible if you are using the absolute values. Are you using the absolute values? Also, 72.71415 is no good. Use 72.7

  23. dan815
    • one year ago
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    pi*r^2 *h |dw:1362879713114:dw|

  24. christine87
    • one year ago
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    im totally stumped this is the exact problem taken off the homework, nothing seems to fit

  25. dan815
    • one year ago
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    i will help you okay!! if you let me help you

  26. dan815
    • one year ago
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    what is your R and H?

  27. christine87
    • one year ago
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    @dan815 ok thank you. . .im given D = 2.7 and H = 12.7 and r is 1/2 of D

  28. tkhunny
    • one year ago
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    Well, 72.7 mL is a rather horrible approximation for a 50.0 mL beaker. Maybe something else went wrong. Or, maybe we're just testing the %-Errors formula. \(\dfrac{|50.0 - 72.7|}{50.00}\cdot 100\;=\;\dfrac{|- 22.7|}{50.00}\cdot 100\;=\;\)

  29. dan815
    • one year ago
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    ok your V = 1.35^2pi*12.7 = 72.7 (72.7-50/50)*100 = ansswer to 2 decimal places

  30. dan815
    • one year ago
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    45.43%

  31. dan815
    • one year ago
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    u understand?

  32. christine87
    • one year ago
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    its a negative number because its the accepted (50) minus the experiemental number, not the other way around thats why im not understanding

  33. dan815
    • one year ago
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    wuts a negative number?

  34. dan815
    • one year ago
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    is the percentage negative?

  35. christine87
    • one year ago
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    the result is negative

  36. dan815
    • one year ago
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    oh okay then its -45.43%

  37. christine87
    • one year ago
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    how is it possible to have a regative as an answer to this particular question tho?

  38. dan815
    • one year ago
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    its possible if its -'ve then it means ur value was 45.43% more than the actual value if its positive then its 45.43% less than the actual value

  39. dan815
    • one year ago
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    though i think your question should say do the absolute value of the percentage of error

  40. dan815
    • one year ago
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    but if they are defining the percentage of error without absolute value then u can get negative values

  41. tkhunny
    • one year ago
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    You are overlooking the Absolute Values. |50.0 - 72.7| = |72.7 - 50.0| = 22.7 There cannot be a negative value resulting from this operation.

  42. christine87
    • one year ago
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    ooohh ok i have no idea i havent been taught absolute values, just thrown this problem set today

  43. dan815
    • one year ago
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    those 2 lines around the numbers mean take the absolute value so whatever the value they are always take the positive of it

  44. christine87
    • one year ago
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    i was given this: Percent Error = /accepted value - experimental value/x 100 accepted value written exactly as it is, no boxes or lines around etc

  45. dan815
    • one year ago
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    the equation for absolute value is this |dw:1362882330695:dw|

  46. dan815
    • one year ago
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    always gives positive answer

  47. dan815
    • one year ago
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    those / / mean absolute value

  48. tkhunny
    • one year ago
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    What are those slanty lines? Those are supposed to be Absolute Value Symbols. Trust me on this.

  49. dan815
    • one year ago
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    i wish u were asian right now-_-

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