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dan815
 one year ago
Best ResponseYou've already chosen the best response.0why dont you substitute those numbers into the formula and solve it

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Divide by \(\pi r^{2}\). \(\left(\pi r^{2}\right)\) is attached to 'h' via multiplication. Detach it via division.

christine87
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 i clearly have done so already, but not coming up with the 'correct' answer according to the rest of the problem i'm inserting it into, hence why I'm seeing if im doing it wrong.

christine87
 one year ago
Best ResponseYou've already chosen the best response.0@tkhunny hi ther, thanks, but i'm not trying to solvefor h, i'm subsituting the numbers i posted above. . . seem to be coming up incorrect according to the book/problem set

dan815
 one year ago
Best ResponseYou've already chosen the best response.0what is the object you are trying to find the integral of?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0?? "Solve V = π r2h for h" Perhaps we're speaking a different language? One might ask, why are nyou not trying to solve for h? Are you studying Significant Figures"? What answer are you giving that is being rejected?

bradely
 one year ago
Best ResponseYou've already chosen the best response.0step by step answers posted here http://www.mathskey.com/question2answer/2063/solvev%CF%80r2hforh ask your Algebra1 homework questions athttp://www.mathskey.com/question2answer/algebra1 and get free math help. all the best

christine87
 one year ago
Best ResponseYou've already chosen the best response.0its a beaker filled with a certain amount of liquid, all a part of a stream of different question s built off this one

christine87
 one year ago
Best ResponseYou've already chosen the best response.0@tkhunny because i HAVE h already, as posted above, im trying to find V

christine87
 one year ago
Best ResponseYou've already chosen the best response.0this is the complete problem : 5. Calculate the volume of the 50mL graduated cylinder using your measurements of diameter and height, using the formula V = ∏ r2h (r=½ diameter). This is your experimental value. Assuming the accepted value of the volume of the graduated cylinder is 50.00 mL, calculate the percent error of your volume calculation, using the following formula: Percent Error = /accepted value  experimental value/x 100 accepted value

dan815
 one year ago
Best ResponseYou've already chosen the best response.0lets compare answers i get for r = 1.35 h = 12.7 pi*2*r*h = 107.725212092

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0That's okay, but I'm really curious how this is consistent with "Solve V = π r2h for h". Anyway, it appears we ARE studying Significant Figures. Now answer the question. What value are you using that is being rejected?

dan815
 one year ago
Best ResponseYou've already chosen the best response.0that is area tho i think you mean pi * r^2 *h = 72.7145181618

christine87
 one year ago
Best ResponseYou've already chosen the best response.0i'm getting 72.7145. . .but when i plug it into the next step in my problem it doesnt make any sense! im getting a negative percentage error

dan815
 one year ago
Best ResponseYou've already chosen the best response.0it says its pir2h so u shud use the other one 107.725212092

dan815
 one year ago
Best ResponseYou've already chosen the best response.0your question is wrong i think it shud say pir^2*2 not pi*r2h

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Well, a negative value isn't possible if you are using the absolute values. Are you using the absolute values? Also, 72.71415 is no good. Use 72.7

dan815
 one year ago
Best ResponseYou've already chosen the best response.0pi*r^2 *h dw:1362879713114:dw

christine87
 one year ago
Best ResponseYou've already chosen the best response.0im totally stumped this is the exact problem taken off the homework, nothing seems to fit

dan815
 one year ago
Best ResponseYou've already chosen the best response.0i will help you okay!! if you let me help you

christine87
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 ok thank you. . .im given D = 2.7 and H = 12.7 and r is 1/2 of D

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Well, 72.7 mL is a rather horrible approximation for a 50.0 mL beaker. Maybe something else went wrong. Or, maybe we're just testing the %Errors formula. \(\dfrac{50.0  72.7}{50.00}\cdot 100\;=\;\dfrac{ 22.7}{50.00}\cdot 100\;=\;\)

dan815
 one year ago
Best ResponseYou've already chosen the best response.0ok your V = 1.35^2pi*12.7 = 72.7 (72.750/50)*100 = ansswer to 2 decimal places

christine87
 one year ago
Best ResponseYou've already chosen the best response.0its a negative number because its the accepted (50) minus the experiemental number, not the other way around thats why im not understanding

dan815
 one year ago
Best ResponseYou've already chosen the best response.0wuts a negative number?

dan815
 one year ago
Best ResponseYou've already chosen the best response.0is the percentage negative?

christine87
 one year ago
Best ResponseYou've already chosen the best response.0the result is negative

dan815
 one year ago
Best ResponseYou've already chosen the best response.0oh okay then its 45.43%

christine87
 one year ago
Best ResponseYou've already chosen the best response.0how is it possible to have a regative as an answer to this particular question tho?

dan815
 one year ago
Best ResponseYou've already chosen the best response.0its possible if its 've then it means ur value was 45.43% more than the actual value if its positive then its 45.43% less than the actual value

dan815
 one year ago
Best ResponseYou've already chosen the best response.0though i think your question should say do the absolute value of the percentage of error

dan815
 one year ago
Best ResponseYou've already chosen the best response.0but if they are defining the percentage of error without absolute value then u can get negative values

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0You are overlooking the Absolute Values. 50.0  72.7 = 72.7  50.0 = 22.7 There cannot be a negative value resulting from this operation.

christine87
 one year ago
Best ResponseYou've already chosen the best response.0ooohh ok i have no idea i havent been taught absolute values, just thrown this problem set today

dan815
 one year ago
Best ResponseYou've already chosen the best response.0those 2 lines around the numbers mean take the absolute value so whatever the value they are always take the positive of it

christine87
 one year ago
Best ResponseYou've already chosen the best response.0i was given this: Percent Error = /accepted value  experimental value/x 100 accepted value written exactly as it is, no boxes or lines around etc

dan815
 one year ago
Best ResponseYou've already chosen the best response.0the equation for absolute value is this dw:1362882330695:dw

dan815
 one year ago
Best ResponseYou've already chosen the best response.0always gives positive answer

dan815
 one year ago
Best ResponseYou've already chosen the best response.0those / / mean absolute value

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0What are those slanty lines? Those are supposed to be Absolute Value Symbols. Trust me on this.

dan815
 one year ago
Best ResponseYou've already chosen the best response.0i wish u were asian right now_
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