Find the intervals on which the function is continous. Y= ^4root(5x-2)

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Find the intervals on which the function is continous. Y= ^4root(5x-2)

Calculus1
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Basically they want you to find intervals where \[ 5x-2\geq0 \]
so I remember my teacher doind something like (5x-2)^1/4 Do I start it like that?
Nah, you really only have to remember that when you have even roots, you can't have negative numbers inside.

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Y= ^4root(5x-2) Can you clean that up? It makes no sense as written.
\[\sqrt[4]{5x-2}\]
its the quad root of 5x-2
OK. If you take an even root of an expression, the expression has to be greater than or = 0: the even root of a negative number is imaginary. (Odd roots of negatives are fine.) So, as wio said, figure out where the radicand (5x - 2) is > or = 0.
Where the function is defined, it's continuous.
so it is defined when x is > or = .4 ?
Yes. Good.

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