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billie4120

  • 3 years ago

Find the intervals on which the function is continous. Y= ^4root(5x-2)

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  1. wio
    • 3 years ago
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    Basically they want you to find intervals where \[ 5x-2\geq0 \]

  2. billie4120
    • 3 years ago
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    so I remember my teacher doind something like (5x-2)^1/4 Do I start it like that?

  3. wio
    • 3 years ago
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    Nah, you really only have to remember that when you have even roots, you can't have negative numbers inside.

  4. NoelGreco
    • 3 years ago
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    Y= ^4root(5x-2) Can you clean that up? It makes no sense as written.

  5. billie4120
    • 3 years ago
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    \[\sqrt[4]{5x-2}\]

  6. billie4120
    • 3 years ago
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    its the quad root of 5x-2

  7. NoelGreco
    • 3 years ago
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    OK. If you take an even root of an expression, the expression has to be greater than or = 0: the even root of a negative number is imaginary. (Odd roots of negatives are fine.) So, as wio said, figure out where the radicand (5x - 2) is > or = 0.

  8. NoelGreco
    • 3 years ago
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    Where the function is defined, it's continuous.

  9. billie4120
    • 3 years ago
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    so it is defined when x is > or = .4 ?

  10. NoelGreco
    • 3 years ago
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    Yes. Good.

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