Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Find the intervals on which the function is continous.
Y= ^4root(5x2)
 one year ago
 one year ago
Find the intervals on which the function is continous. Y= ^4root(5x2)
 one year ago
 one year ago

This Question is Closed

wioBest ResponseYou've already chosen the best response.0
Basically they want you to find intervals where \[ 5x2\geq0 \]
 one year ago

billie4120Best ResponseYou've already chosen the best response.0
so I remember my teacher doind something like (5x2)^1/4 Do I start it like that?
 one year ago

wioBest ResponseYou've already chosen the best response.0
Nah, you really only have to remember that when you have even roots, you can't have negative numbers inside.
 one year ago

NoelGrecoBest ResponseYou've already chosen the best response.0
Y= ^4root(5x2) Can you clean that up? It makes no sense as written.
 one year ago

billie4120Best ResponseYou've already chosen the best response.0
its the quad root of 5x2
 one year ago

NoelGrecoBest ResponseYou've already chosen the best response.0
OK. If you take an even root of an expression, the expression has to be greater than or = 0: the even root of a negative number is imaginary. (Odd roots of negatives are fine.) So, as wio said, figure out where the radicand (5x  2) is > or = 0.
 one year ago

NoelGrecoBest ResponseYou've already chosen the best response.0
Where the function is defined, it's continuous.
 one year ago

billie4120Best ResponseYou've already chosen the best response.0
so it is defined when x is > or = .4 ?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.