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anonymous
 3 years ago
Integral Question
anonymous
 3 years ago
Integral Question

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{4} \frac{ dx }{ (x2)^{2/3} }\]

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.3You ARE going to have to cut it up at x = 2 and consider convergence on both sides.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Split it and take limit approaching 2 from left and right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int_0^4\frac{dx}{(x2)^{\frac{2}{3}}}=\int_0^2\frac{dx}{(x2)^{\frac{2}{3}}}+\int_2^4\frac{dx}{(x2)^{\frac{2}{3}}}\] The integrand is undefined at x = 2, so you'll have to split up the integrals and take limits.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How do I take the integral of [1/(x2)]^(2/3)

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.3Simple exponent. \(\int [1/(x2)]^{2/3}\;dx = \int [x2]^{2/3}\;dx = \dfrac{(x2)^{1/3}}{1/3} + C\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Gah... How did I miss that. Thanks.
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