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j814wongBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{4} \frac{ dx }{ (x2)^{2/3} }\]
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.3
You ARE going to have to cut it up at x = 2 and consider convergence on both sides.
 one year ago

j814wongBest ResponseYou've already chosen the best response.0
Split it and take limit approaching 2 from left and right?
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.0
\[\int_0^4\frac{dx}{(x2)^{\frac{2}{3}}}=\int_0^2\frac{dx}{(x2)^{\frac{2}{3}}}+\int_2^4\frac{dx}{(x2)^{\frac{2}{3}}}\] The integrand is undefined at x = 2, so you'll have to split up the integrals and take limits.
 one year ago

j814wongBest ResponseYou've already chosen the best response.0
How do I take the integral of [1/(x2)]^(2/3)
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.3
Simple exponent. \(\int [1/(x2)]^{2/3}\;dx = \int [x2]^{2/3}\;dx = \dfrac{(x2)^{1/3}}{1/3} + C\)
 one year ago

j814wongBest ResponseYou've already chosen the best response.0
Gah... How did I miss that. Thanks.
 one year ago
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