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anonymous
 3 years ago
Help please
Find a particular solution of the given equation:
y"5'+2y=(26x2x^2) e^x
anonymous
 3 years ago
Help please Find a particular solution of the given equation: y"5'+2y=(26x2x^2) e^x

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dumbcow
 3 years ago
Best ResponseYou've already chosen the best response.1this would be more help than i could give http://www.wolframalpha.com/input/?i=y%27%275y%27%2B2y+%3D+2e^x%2813xx^2%29 if you register with site you can see stepbystep solution also to get particular solution you need initial values?

dumbcow
 3 years ago
Best ResponseYou've already chosen the best response.1to get you started, always solve the characteristic equation r^2 5r +2 = 0 \[r = \frac{5 \pm \sqrt{17}}{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As for the particular solution, as a guess, try \[y_p=e^x(Ax^2+Bx+C)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You might need "variation of parameters" here.
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