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Find a particular solution of the given equation:
y"5'+2y=(26x2x^2) e^x
 one year ago
 one year ago
Help please Find a particular solution of the given equation: y"5'+2y=(26x2x^2) e^x
 one year ago
 one year ago

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dumbcowBest ResponseYou've already chosen the best response.1
this would be more help than i could give http://www.wolframalpha.com/input/?i=y%27%275y%27%2B2y+%3D+2e^x%2813xx^2%29 if you register with site you can see stepbystep solution also to get particular solution you need initial values?
 one year ago

dumbcowBest ResponseYou've already chosen the best response.1
to get you started, always solve the characteristic equation r^2 5r +2 = 0 \[r = \frac{5 \pm \sqrt{17}}{2}\]
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.0
As for the particular solution, as a guess, try \[y_p=e^x(Ax^2+Bx+C)\]
 one year ago

dlipson1Best ResponseYou've already chosen the best response.0
You might need "variation of parameters" here.
 one year ago
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