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 one year ago
Help please
Find a particular solution of the given equation:
y"5'+2y=(26x2x^2) e^x
 one year ago
Help please Find a particular solution of the given equation: y"5'+2y=(26x2x^2) e^x

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dumbcow
 one year ago
Best ResponseYou've already chosen the best response.1this would be more help than i could give http://www.wolframalpha.com/input/?i=y%27%275y%27%2B2y+%3D+2e^x%2813xx^2%29 if you register with site you can see stepbystep solution also to get particular solution you need initial values?

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.1to get you started, always solve the characteristic equation r^2 5r +2 = 0 \[r = \frac{5 \pm \sqrt{17}}{2}\]

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0As for the particular solution, as a guess, try \[y_p=e^x(Ax^2+Bx+C)\]

dlipson1
 one year ago
Best ResponseYou've already chosen the best response.0You might need "variation of parameters" here.
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