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\[\int\limits \tan x dx = \int\limits \frac{ \sin x }{ \cos x } dx\]

i know i even get the answer \[\ln (\sec) + C\]
But I can't find any error

read the question it says whts the error in converting tan to sin/cos

we need calculus teachers here...not the correct answer

no brackets should be integral (sinx/cosx)dx

what

\[\int\limits tanx dx = \int\limits (\frac{ sinx }{ cosx } )dx\]

cmon this is not the answer this doesn't even look like an error dude

lol just guessing maybe its this

dude i m frikin out lol

correction \[-ln|cosx|+C\]

ya so whats the error

i know i know...i got this answer too...but i can't understand what is the error...read the question

it asks for the error in converting tan to sin/cos

ok i guess...i said the same thing to my teacher but she said no there is one

haha

ha, really? that is odd. did you google it?

ya no help from there...google told me to come here haha

what lol...say it again confused

h/o a minute

ok ok

lol...no idea to this man.....

haha...i am never gonna figure it out XD

I will copy it and show it to my lecturer and will get back to you

sweet...dont forget to get the equation from comment box

yeah, I copied it

thx tell me ASAP plz

@amistre64 can u solve this

.... that i can determine

haha...but there is an error idk wht

@inkyvoyd ...that would make so much more sense

did you ask your instructor?

The error is that "an error exists" itself then, I believe. Please ask your instructor :)

just watch this question

There is no error in the OP. int(tanx)=int(sinx/cosx)=lnabs(secx)

wrong answer

will reply the correct one asap