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Simplify. Show work and explain.
13. n^5 over n  6 * n^2  6n over n^8
 one year ago
 one year ago
Simplify. Show work and explain. 13. n^5 over n  6 * n^2  6n over n^8
 one year ago
 one year ago

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MertsjBest ResponseYou've already chosen the best response.1
Factor 3y^2 out of the numerator
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
Remember to multiply by the reciprocal and factor n^26n by factoring out n
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
so now we have n^5 * n over n^8
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
\[\frac{n^5}{n6}\times\frac{n(n6)}{n^8}=\frac{1}{n^2}\]
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
I need someone to finish Mertsj's work
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large \frac{n^5}{n6}\times \frac{n^26n}{n^8}\] Hmm do you understand what he did so far? That was a bunch of steps all done at once, I can understand if it was a little confusing.
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
I understand that, but I need the explanation of how that = 1 over n^2
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large \frac{n^5}{n6}\times \frac{\color{orangered}{n^26n}}{n^8}\] For this orange part, factor an n out of each term.\[\large \frac{n^5}{n6}\times \frac{\color{orangered}{n(n6)}}{n^8}\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
From here we'll simply multiply across, Put brackets around the n6 on the bottom, so the multiplication is a little clearer.\[\large \frac{n^5}{(n6)}\times \frac{n(n6)}{n^8}\] Then multiplying across gives us,\[\large \frac{n^5\times n(n6)}{n^8(n6)} \qquad = \qquad \frac{n^6(n6)}{n^8(n6)}\]Understand so far? :o
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
The n6's can divide out,\[\large \frac{n^6\cancel{(n6)}}{n^8\cancel{(n6)}} \qquad = \qquad \frac{n^6}{n^8}\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
From here, we want to remember our rules for exponents. When we divide terms of the same base, we `subtract` the exponents.\[\large \frac{n^6}{n^8} \qquad = \qquad n^{68}\]
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
then's it's 1 over n^2
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large n^{2}\qquad = \qquad \frac{1}{n^2}\]Yes :)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
you can do that OR the biggest exponent is on the bottom < 8  6 = 2
 one year ago
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