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Firejay5
Group Title
Simplify. Show work and explain.
13. n^5 over n  6 * n^2  6n over n^8
 one year ago
 one year ago
Firejay5 Group Title
Simplify. Show work and explain. 13. n^5 over n  6 * n^2  6n over n^8
 one year ago
 one year ago

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Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Factor 3y^2 out of the numerator
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Remember to multiply by the reciprocal and factor n^26n by factoring out n
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
cancel out n  6
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
so now we have n^5 * n over n^8
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{n^5}{n6}\times\frac{n(n6)}{n^8}=\frac{1}{n^2}\]
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
I need someone to finish Mertsj's work
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large \frac{n^5}{n6}\times \frac{n^26n}{n^8}\] Hmm do you understand what he did so far? That was a bunch of steps all done at once, I can understand if it was a little confusing.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
I understand that, but I need the explanation of how that = 1 over n^2
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large \frac{n^5}{n6}\times \frac{\color{orangered}{n^26n}}{n^8}\] For this orange part, factor an n out of each term.\[\large \frac{n^5}{n6}\times \frac{\color{orangered}{n(n6)}}{n^8}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
From here we'll simply multiply across, Put brackets around the n6 on the bottom, so the multiplication is a little clearer.\[\large \frac{n^5}{(n6)}\times \frac{n(n6)}{n^8}\] Then multiplying across gives us,\[\large \frac{n^5\times n(n6)}{n^8(n6)} \qquad = \qquad \frac{n^6(n6)}{n^8(n6)}\]Understand so far? :o
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
The n6's can divide out,\[\large \frac{n^6\cancel{(n6)}}{n^8\cancel{(n6)}} \qquad = \qquad \frac{n^6}{n^8}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
From here, we want to remember our rules for exponents. When we divide terms of the same base, we `subtract` the exponents.\[\large \frac{n^6}{n^8} \qquad = \qquad n^{68}\]
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
then's it's 1 over n^2
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large n^{2}\qquad = \qquad \frac{1}{n^2}\]Yes :)
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
you can do that OR the biggest exponent is on the bottom < 8  6 = 2
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
substract
 one year ago
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