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I need help figuring out how the derivative of the graph would look approximatially.
 one year ago
 one year ago
I need help figuring out how the derivative of the graph would look approximatially.
 one year ago
 one year ago

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farmergirl411Best ResponseYou've already chosen the best response.0
dw:1362964903781:dw
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
This is the original graph how would the derivative look
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362965404144:dwThese are the easy points to start with. Draw tangent lines. See how the slope of these tangent lines is 0. That means the VALUE of the derivative function will be zero.
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
so then the derivative just goes along the x line
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
No, the derivative passes through the xaxis at those 3 points :) now let's find some other points.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362965586761:dwUnderstand how I drew the line tangent to the curve? See how it's pointing downward (read from left to right). It has an extremely negative slope. Meaning the derivative function will have an extremely negative VALUE at this x coordinate.
 one year ago

ahdreaonnaBest ResponseYou've already chosen the best response.0
well then there you ave it
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362965734778:dwNow the function is starting to come together! c:
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Have you learned about inflection points? :o Is this all too confusing farmergal? :c
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
no so then does it just go up to the x line then hit the dots on the x line.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Yes, but it will keep going past the x line, how far? Well until we reach the inflection point.
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
Now I'm confussed when you say it keeps going to the inflection point.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362965901972:dwRight around that point, it changes from `Concave Up` to `Concave Down`.
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
dw:1362965979553:dwSO it will look like this
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Ummmm yah it looks like that's where we're headed :)
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
ok I got it so far.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362966148110:dwSo at that x coordinate, our derivative function reaches the bottom of the bowl :D
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1362966245521:dwIf we check one last point way on the right over here, it appears to be very positive slope, so the derivative function will have a very positive value.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Something like that, the original graph was a tad sloppy. So it's hard to say for certain :) heh
 one year ago

farmergirl411Best ResponseYou've already chosen the best response.0
ok got it thanks
 one year ago
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