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farmergirl411
 2 years ago
I need help figuring out how the derivative of the graph would look approximatially.
farmergirl411
 2 years ago
I need help figuring out how the derivative of the graph would look approximatially.

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farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1362964903781:dw

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0This is the original graph how would the derivative look

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362965404144:dwThese are the easy points to start with. Draw tangent lines. See how the slope of these tangent lines is 0. That means the VALUE of the derivative function will be zero.

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0so then the derivative just goes along the x line

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1No, the derivative passes through the xaxis at those 3 points :) now let's find some other points.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362965586761:dwUnderstand how I drew the line tangent to the curve? See how it's pointing downward (read from left to right). It has an extremely negative slope. Meaning the derivative function will have an extremely negative VALUE at this x coordinate.

ahdreaonna
 2 years ago
Best ResponseYou've already chosen the best response.0well then there you ave it

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362965734778:dwNow the function is starting to come together! c:

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Have you learned about inflection points? :o Is this all too confusing farmergal? :c

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0no so then does it just go up to the x line then hit the dots on the x line.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, but it will keep going past the x line, how far? Well until we reach the inflection point.

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0Now I'm confussed when you say it keeps going to the inflection point.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362965901972:dwRight around that point, it changes from `Concave Up` to `Concave Down`.

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1362965979553:dwSO it will look like this

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Ummmm yah it looks like that's where we're headed :)

farmergirl411
 2 years ago
Best ResponseYou've already chosen the best response.0ok I got it so far.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362966148110:dwSo at that x coordinate, our derivative function reaches the bottom of the bowl :D

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1362966245521:dwIf we check one last point way on the right over here, it appears to be very positive slope, so the derivative function will have a very positive value.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Something like that, the original graph was a tad sloppy. So it's hard to say for certain :) heh
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