anonymous
  • anonymous
I need help figuring out how the derivative of the graph would look approximatially.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1362964903781:dw|
anonymous
  • anonymous
This is the original graph how would the derivative look
anonymous
  • anonymous
rigth

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anonymous
  • anonymous
so
zepdrix
  • zepdrix
|dw:1362965404144:dw|These are the easy points to start with. Draw tangent lines. See how the slope of these tangent lines is 0. That means the VALUE of the derivative function will be zero.
zepdrix
  • zepdrix
|dw:1362965478556:dw|
anonymous
  • anonymous
so then the derivative just goes along the x line
zepdrix
  • zepdrix
No, the derivative passes through the x-axis at those 3 points :) now let's find some other points.
anonymous
  • anonymous
ok
zepdrix
  • zepdrix
|dw:1362965586761:dw|Understand how I drew the line tangent to the curve? See how it's pointing downward (read from left to right). It has an extremely negative slope. Meaning the derivative function will have an extremely negative VALUE at this x coordinate.
zepdrix
  • zepdrix
|dw:1362965677365:dw|
anonymous
  • anonymous
ok
anonymous
  • anonymous
well then there you ave it
zepdrix
  • zepdrix
|dw:1362965734778:dw|Now the function is starting to come together! c:
zepdrix
  • zepdrix
Have you learned about inflection points? :o Is this all too confusing farmergal? :c
anonymous
  • anonymous
no so then does it just go up to the x line then hit the dots on the x line.
zepdrix
  • zepdrix
Yes, but it will keep going past the x line, how far? Well until we reach the inflection point.
anonymous
  • anonymous
Now I'm confussed when you say it keeps going to the inflection point.
zepdrix
  • zepdrix
|dw:1362965901972:dw|Right around that point, it changes from `Concave Up` to `Concave Down`.
anonymous
  • anonymous
|dw:1362965979553:dw|SO it will look like this
zepdrix
  • zepdrix
|dw:1362965980976:dw|
zepdrix
  • zepdrix
Ummmm yah it looks like that's where we're headed :)
anonymous
  • anonymous
ok I got it so far.
zepdrix
  • zepdrix
|dw:1362966105601:dw|
anonymous
  • anonymous
ok
zepdrix
  • zepdrix
|dw:1362966148110:dw|So at that x coordinate, our derivative function reaches the bottom of the bowl :D
anonymous
  • anonymous
ok go it
zepdrix
  • zepdrix
|dw:1362966245521:dw|If we check one last point way on the right over here, it appears to be very positive slope, so the derivative function will have a very positive value.
zepdrix
  • zepdrix
|dw:1362966295539:dw|
zepdrix
  • zepdrix
Something like that, the original graph was a tad sloppy. So it's hard to say for certain :) heh
anonymous
  • anonymous
ok got it thanks

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