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farmergirl411 Group Title

I need help figuring out how the derivative of the graph would look approximatially.

  • one year ago
  • one year ago

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  1. farmergirl411 Group Title
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    |dw:1362964903781:dw|

    • one year ago
  2. farmergirl411 Group Title
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    This is the original graph how would the derivative look

    • one year ago
  3. ahdreaonna Group Title
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    rigth

    • one year ago
  4. ahdreaonna Group Title
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    so

    • one year ago
  5. zepdrix Group Title
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    |dw:1362965404144:dw|These are the easy points to start with. Draw tangent lines. See how the slope of these tangent lines is 0. That means the VALUE of the derivative function will be zero.

    • one year ago
  6. zepdrix Group Title
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    |dw:1362965478556:dw|

    • one year ago
  7. farmergirl411 Group Title
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    so then the derivative just goes along the x line

    • one year ago
  8. zepdrix Group Title
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    No, the derivative passes through the x-axis at those 3 points :) now let's find some other points.

    • one year ago
  9. farmergirl411 Group Title
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    ok

    • one year ago
  10. zepdrix Group Title
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    |dw:1362965586761:dw|Understand how I drew the line tangent to the curve? See how it's pointing downward (read from left to right). It has an extremely negative slope. Meaning the derivative function will have an extremely negative VALUE at this x coordinate.

    • one year ago
  11. zepdrix Group Title
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    |dw:1362965677365:dw|

    • one year ago
  12. farmergirl411 Group Title
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    ok

    • one year ago
  13. ahdreaonna Group Title
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    well then there you ave it

    • one year ago
  14. zepdrix Group Title
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    |dw:1362965734778:dw|Now the function is starting to come together! c:

    • one year ago
  15. zepdrix Group Title
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    Have you learned about inflection points? :o Is this all too confusing farmergal? :c

    • one year ago
  16. farmergirl411 Group Title
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    no so then does it just go up to the x line then hit the dots on the x line.

    • one year ago
  17. zepdrix Group Title
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    Yes, but it will keep going past the x line, how far? Well until we reach the inflection point.

    • one year ago
  18. farmergirl411 Group Title
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    Now I'm confussed when you say it keeps going to the inflection point.

    • one year ago
  19. zepdrix Group Title
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    |dw:1362965901972:dw|Right around that point, it changes from `Concave Up` to `Concave Down`.

    • one year ago
  20. farmergirl411 Group Title
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    |dw:1362965979553:dw|SO it will look like this

    • one year ago
  21. zepdrix Group Title
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    |dw:1362965980976:dw|

    • one year ago
  22. zepdrix Group Title
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    Ummmm yah it looks like that's where we're headed :)

    • one year ago
  23. farmergirl411 Group Title
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    ok I got it so far.

    • one year ago
  24. zepdrix Group Title
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    |dw:1362966105601:dw|

    • one year ago
  25. farmergirl411 Group Title
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    ok

    • one year ago
  26. zepdrix Group Title
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    |dw:1362966148110:dw|So at that x coordinate, our derivative function reaches the bottom of the bowl :D

    • one year ago
  27. farmergirl411 Group Title
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    ok go it

    • one year ago
  28. zepdrix Group Title
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    |dw:1362966245521:dw|If we check one last point way on the right over here, it appears to be very positive slope, so the derivative function will have a very positive value.

    • one year ago
  29. zepdrix Group Title
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    |dw:1362966295539:dw|

    • one year ago
  30. zepdrix Group Title
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    Something like that, the original graph was a tad sloppy. So it's hard to say for certain :) heh

    • one year ago
  31. farmergirl411 Group Title
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    ok got it thanks

    • one year ago
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