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Has anyone proved that y=2y zero on that problem in the first lecture where he used symmetry to get that y=2y zero? Could you help because I keep getting y=2/x zero.
 one year ago
 one year ago
Has anyone proved that y=2y zero on that problem in the first lecture where he used symmetry to get that y=2y zero? Could you help because I keep getting y=2/x zero.
 one year ago
 one year ago

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StaceyBest ResponseYou've already chosen the best response.0
I would need to see the actual problem.
 one year ago

pryan1Best ResponseYou've already chosen the best response.0
yy zero=1/(x zero)^2 (xx zero) is the problem. The professor solved for x by plugging in y=0 and got x=2x zero which I understand. Then he said by symmetry you get y=2y zero and we could prove it by taking the same equation and plugging in x=0. Every time I do that, I get y= 2/x zero, not y=2y.
 one year ago

StaceyBest ResponseYou've already chosen the best response.0
Based on what you are saying, I am assuming that previously in the lecture, it was stated that \[y _{0} = \frac{ 1 }{ x _{0} }\]If that is the case, then \[x _{0} = \frac{ 1 }{ y _{0} }\] and \[y=2y _{0}\]
 one year ago

pryan1Best ResponseYou've already chosen the best response.0
i must be doing something wrong...thanks anyway
 one year ago

sanghvitkBest ResponseYou've already chosen the best response.0
The area of the triangle as he derives is 2XoYo. As y = f(x) = 1/X, f(Xo) = 1/Xo. Therefore Yo = 1/Xo. Thus, 2XoYo = 2Xo(1/Xo) = 2
 one year ago
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