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 2 years ago
Has anyone proved that y=2y zero on that problem in the first lecture where he used symmetry to get that y=2y zero? Could you help because I keep getting y=2/x zero.
 2 years ago
Has anyone proved that y=2y zero on that problem in the first lecture where he used symmetry to get that y=2y zero? Could you help because I keep getting y=2/x zero.

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Stacey
 2 years ago
Best ResponseYou've already chosen the best response.0I would need to see the actual problem.

pryan1
 2 years ago
Best ResponseYou've already chosen the best response.0yy zero=1/(x zero)^2 (xx zero) is the problem. The professor solved for x by plugging in y=0 and got x=2x zero which I understand. Then he said by symmetry you get y=2y zero and we could prove it by taking the same equation and plugging in x=0. Every time I do that, I get y= 2/x zero, not y=2y.

Stacey
 2 years ago
Best ResponseYou've already chosen the best response.0Based on what you are saying, I am assuming that previously in the lecture, it was stated that \[y _{0} = \frac{ 1 }{ x _{0} }\]If that is the case, then \[x _{0} = \frac{ 1 }{ y _{0} }\] and \[y=2y _{0}\]

pryan1
 2 years ago
Best ResponseYou've already chosen the best response.0i must be doing something wrong...thanks anyway

sanghvitk
 one year ago
Best ResponseYou've already chosen the best response.0The area of the triangle as he derives is 2XoYo. As y = f(x) = 1/X, f(Xo) = 1/Xo. Therefore Yo = 1/Xo. Thus, 2XoYo = 2Xo(1/Xo) = 2
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