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sophiashaikh

  • 3 years ago

Can someone help me on a relations and functions question .....I'll post the question

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  1. sophiashaikh
    • 3 years ago
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  2. LifeIsADangerousGame
    • 3 years ago
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    Alright, here's how to solve B. For the first week (7 days) it's 20 dollars per day so it's $20 x 7 = ? Then the last three days it's 17 dollars (since the price goes down) so it's $17 * 3 = ? Multiply those two and then add up the products and that'll be the answer for b

  3. sophiashaikh
    • 3 years ago
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    I got 191

  4. LifeIsADangerousGame
    • 3 years ago
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    Here's how to solve c. For the first time she parked at the garage, she had the car there for five days so it's $20 x 5 = ? For the second time she parked there, she was there for more than 7 days so first it's $20 x 7 = ? And the last day she was there was $17 so whatever your answer is for $20 x 7 you add 17 dollars to and that'll be your answer.

  5. LifeIsADangerousGame
    • 3 years ago
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    Let me check

  6. LifeIsADangerousGame
    • 3 years ago
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    $191 is correct (I really hope I'm doing this right :b ) is this k12?

  7. sophiashaikh
    • 3 years ago
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    yes it is lol

  8. sophiashaikh
    • 3 years ago
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    I got 257 for C now what? lol

  9. LifeIsADangerousGame
    • 3 years ago
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    That's what I got too..I'm guessing that's right :b

  10. sophiashaikh
    • 3 years ago
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    so the differnce would be $57?

  11. jim_thompson5910
    • 3 years ago
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    for part a) it costs $20 a day for the first week so if f(x) is the cost function, then f(x) = 20x if 0 <= x <= 7 (this is the initial charge per day) OR f(x) = 17x if x > 7 (because the cost decreases to $17 a day after 7 days)

  12. jim_thompson5910
    • 3 years ago
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    where x = number of days parked

  13. sophiashaikh
    • 3 years ago
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    Okay that makes sense thank you

  14. jim_thompson5910
    • 3 years ago
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    yw

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