anonymous
  • anonymous
Can someone help me on a relations and functions question .....I'll post the question
Algebra
katieb
  • katieb
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anonymous
  • anonymous
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LifeIsADangerousGame
  • LifeIsADangerousGame
Alright, here's how to solve B. For the first week (7 days) it's 20 dollars per day so it's $20 x 7 = ? Then the last three days it's 17 dollars (since the price goes down) so it's $17 * 3 = ? Multiply those two and then add up the products and that'll be the answer for b
anonymous
  • anonymous
I got 191

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LifeIsADangerousGame
  • LifeIsADangerousGame
Here's how to solve c. For the first time she parked at the garage, she had the car there for five days so it's $20 x 5 = ? For the second time she parked there, she was there for more than 7 days so first it's $20 x 7 = ? And the last day she was there was $17 so whatever your answer is for $20 x 7 you add 17 dollars to and that'll be your answer.
LifeIsADangerousGame
  • LifeIsADangerousGame
Let me check
LifeIsADangerousGame
  • LifeIsADangerousGame
$191 is correct (I really hope I'm doing this right :b ) is this k12?
anonymous
  • anonymous
yes it is lol
anonymous
  • anonymous
I got 257 for C now what? lol
LifeIsADangerousGame
  • LifeIsADangerousGame
That's what I got too..I'm guessing that's right :b
anonymous
  • anonymous
so the differnce would be $57?
jim_thompson5910
  • jim_thompson5910
for part a) it costs $20 a day for the first week so if f(x) is the cost function, then f(x) = 20x if 0 <= x <= 7 (this is the initial charge per day) OR f(x) = 17x if x > 7 (because the cost decreases to $17 a day after 7 days)
jim_thompson5910
  • jim_thompson5910
where x = number of days parked
anonymous
  • anonymous
Okay that makes sense thank you
jim_thompson5910
  • jim_thompson5910
yw

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