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Emily778

Find the length of the missing side. Leave your answer in simplest radical form. The triangle is not drawn to scale.

  • one year ago
  • one year ago

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  1. Emily778
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    • one year ago
  2. jim_thompson5910
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    a^2 + b^2 = c^2 5^2 + 13^2 = c^2 solve for c

    • one year ago
  3. Emily778
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    159^2?

    • one year ago
  4. jim_thompson5910
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    5^2 + 13^2 = c^2 25 + 169 = c^2 194 = c^2 c^2 = 194 c = ???

    • one year ago
  5. Emily778
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    I don't know.

    • one year ago
  6. jim_thompson5910
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    what undoes a square?

    • one year ago
  7. Emily778
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    is it sqrt 194?

    • one year ago
  8. jim_thompson5910
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    you got it

    • one year ago
  9. jim_thompson5910
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    the missing side is \[\Large \sqrt{194}\] units

    • one year ago
  10. Emily778
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    is that the answer?

    • one year ago
  11. jim_thompson5910
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    yes

    • one year ago
  12. Emily778
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    A triangle has sides of lengths 27, 79, and 84. Is it a right triangle? Explain. (1 point) yes; 272 + 792 842 no; 272 + 792 = 842 no; 272 + 792 842 yes; 272 + 792 = 842

    • one year ago
  13. jim_thompson5910
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    what is 27^2 + 79^2

    • one year ago
  14. Emily778
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    6,970

    • one year ago
  15. jim_thompson5910
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    what is 84^2

    • one year ago
  16. Emily778
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    7,056

    • one year ago
  17. jim_thompson5910
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    so 6970 is not equal to 7056 which means 27^2 + 79^2 is not equal to 84^2

    • one year ago
  18. jim_thompson5910
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    so that proves you don't have a right triangle

    • one year ago
  19. Emily778
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    so, it's b?

    • one year ago
  20. jim_thompson5910
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    what does C say

    • one year ago
  21. jim_thompson5910
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    it seems like a symbol is missing

    • one year ago
  22. Emily778
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    It's = sign with a line through it.

    • one year ago
  23. jim_thompson5910
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    like this |dw:1362982562480:dw| ??

    • one year ago
  24. jim_thompson5910
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    if so, then it's C

    • one year ago
  25. Emily778
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    yeah, it does look like that. What's that mean?

    • one year ago
  26. jim_thompson5910
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    it means "not equal"

    • one year ago
  27. Emily778
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    oh, so it is C

    • one year ago
  28. jim_thompson5910
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    it's kinda like a "no smoking" sign where it's crossed out

    • one year ago
  29. jim_thompson5910
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    yes

    • one year ago
  30. Emily778
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    A triangle has side lengths of 12 cm, 35 cm, and 37 cm. Classify it as acute, obtuse, or right. (1 point) acute obtuse right

    • one year ago
  31. jim_thompson5910
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    12^2 + 35^2 is what

    • one year ago
  32. Emily778
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    1,369

    • one year ago
  33. jim_thompson5910
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    37^2 is _____

    • one year ago
  34. Emily778
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    1,369

    • one year ago
  35. jim_thompson5910
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    the two are the same, so 12^2 + 35^2 = 37^2

    • one year ago
  36. jim_thompson5910
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    which means that you have a right triangle

    • one year ago
  37. Emily778
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    one more? :)

    • one year ago
  38. jim_thompson5910
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    go for it

    • one year ago
  39. Emily778
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    oops. I don't know how I typed that. That was weird. :/

    • one year ago
  40. Emily778
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    . Find the value of the variable. If your answer is not an integer, leave it in simplest radical form. The triangle is not drawn to scale. (1 point) Find the value of the variable. If your answer is not an integer, leave it in simplest radical form. The triangle is not drawn to scale.

    • one year ago
  41. Emily778
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    woah..Didn't mean to say that twice

    • one year ago
  42. jim_thompson5910
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    that's ok, yeah OS has its glitches from time to time

    • one year ago
  43. jim_thompson5910
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    so you basically want to find x right?

    • one year ago
  44. Emily778
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    I don't know. These are the possible answers.

    • one year ago
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  45. Emily778
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    • one year ago
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  46. Emily778
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  47. jim_thompson5910
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    if so, then a^2 + b^2 = c^2 x^2 + x^2 = 7^2 2x^2 = 49 x^2 = 49/2 x = sqrt(49/2) x = sqrt(49)/sqrt(2) x = 7/sqrt(2) x = 7sqrt(2)/sqrt(2)*sqrt(2) x = 7sqrt(2)/2 So |dw:1362983836880:dw|

    • one year ago
  48. Emily778
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    • one year ago
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  49. jim_thompson5910
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    this one http://assets.openstudy.com/updates/attachments/513d6ea3e4b029b0182b91d9-emily778-1362983851413-mc0063.jpg

    • one year ago
  50. Emily778
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    okay, thanks :)

    • one year ago
  51. jim_thompson5910
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    you're welcome

    • one year ago
  52. Emily778
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    The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter.

    • one year ago
  53. Emily778
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    DO YOU KNOW THIS ONE? D:

    • one year ago
  54. jim_thompson5910
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    did you put on your THINKING CAPS ? lol jk

    • one year ago
  55. jim_thompson5910
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    we know this much |dw:1362983975619:dw|

    • one year ago
  56. jim_thompson5910
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    that's what we're given

    • one year ago
  57. jim_thompson5910
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    the hypotenuse is twice as long as the shorter leg, so the hypotenuse is 2*3 = 6

    • one year ago
  58. jim_thompson5910
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    |dw:1362984054235:dw|

    • one year ago
  59. jim_thompson5910
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    the longer leg is sqrt(3) times longer than the shorter leg so the longer leg is 3*sqrt(3)

    • one year ago
  60. jim_thompson5910
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    |dw:1362984092454:dw|

    • one year ago
  61. jim_thompson5910
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    Now add up all the sides \[\Large 3+6+3\sqrt{3}\] \[\Large 9+3\sqrt{3}\]

    • one year ago
  62. Emily778
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    14.19

    • one year ago
  63. jim_thompson5910
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    that's the approximate perimeter, good

    • one year ago
  64. Emily778
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    that's not one of the answers

    • one year ago
  65. jim_thompson5910
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    ok what are your answers

    • one year ago
  66. Emily778
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    x= 13, y=39 sqrt 3 x= 13 sqrt 3, y=39 x=39,y= 13 sqrt 3 x=39 sqrt 3, y=13

    • one year ago
  67. jim_thompson5910
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    something seems missing

    • one year ago
  68. jim_thompson5910
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    it wanted the perimeter, not x and y whatever those values refer to

    • one year ago
  69. Emily778
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    x and y are the perimeters.

    • one year ago
  70. jim_thompson5910
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    a triangle only has one perimeter

    • one year ago
  71. jim_thompson5910
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    is there a way you can post a screenshot of this problem?

    • one year ago
  72. Emily778
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    Well, it's like an upside down triangle.

    • one year ago
  73. Emily778
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    so, I guess the base is Y

    • one year ago
  74. jim_thompson5910
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    is a screenshot not possible?

    • one year ago
  75. Emily778
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    • one year ago
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  76. jim_thompson5910
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    this looks like a totally different problem what happened with the one "The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter."

    • one year ago
  77. jim_thompson5910
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    odd

    • one year ago
  78. jim_thompson5910
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    so this is the real problem? the other problem wasn't the one you wanted to do?

    • one year ago
  79. Emily778
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    Oh my gosh. I'm so tired. I gave you another problem..

    • one year ago
  80. jim_thompson5910
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    i see, we can do this tomorrow if you want

    • one year ago
  81. Emily778
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    @jim_thompson5910

    • one year ago
  82. Emily778
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    The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter. (1 point) 9/2 + 3/2 sqrt 3 3/2 +9/2 sqrt 3 3+9 sqrt 3 9+3 sqrt 3

    • one year ago
  83. Emily778
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    @jim_thompson5910

    • one year ago
  84. jim_thompson5910
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    we did this one already |dw:1363121467711:dw|

    • one year ago
  85. jim_thompson5910
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    3+6 + 3*sqrt(3) 9 + 3*sqrt(3)

    • one year ago
  86. Emily778
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    I got 14.19

    • one year ago
  87. jim_thompson5910
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    Leave it in radical form So it would be \[\Large 9 + 3\sqrt{3}\]

    • one year ago
  88. Emily778
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    so, it's d?

    • one year ago
  89. jim_thompson5910
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    yes

    • one year ago
  90. Emily778
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    Thankyou. can you help me with more?

    • one year ago
  91. Emily778
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    Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form. This triangle is not drawn to scale. (1 point) x = 13, y = 39 sqrt 3 x = 13 sqrt 3, y = 39 x = 39, y = 13 sqrt 3 x = 39 sqrt 3, y = 13

    • one year ago
  92. Emily778
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    • one year ago
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  93. Emily778
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    @jim_thompson5910

    • one year ago
  94. jim_thompson5910
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    we did this one too

    • one year ago
  95. jim_thompson5910
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    hmm

    • one year ago
  96. jim_thompson5910
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    do you remember doing this?

    • one year ago
  97. Emily778
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    we didn't. I accidentally mixed this one with the other one, though

    • one year ago
  98. jim_thompson5910
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    alright, the shorter leg is half of the hypotenuse so the shorter leg is 13*sqrt(3) this means y = 13*sqrt(3)

    • one year ago
  99. Emily778
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    okay

    • one year ago
  100. jim_thompson5910
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    the longer leg is sqrt(3) times longer than the shorter leg, so... x = y*sqrt(3) x = 13*sqrt(3)*sqrt(3) x = 13*3 x = 39

    • one year ago
  101. Emily778
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    what's y=?

    • one year ago
  102. jim_thompson5910
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    \[\Large y = 13\sqrt{3}\]

    • one year ago
  103. Emily778
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    Do you get this? A conveyor belt carries supplies from the first floor to the second floor, which is 27 feet higher. The belt makes a 60° angle with the ground. How far do the supplies travel from one end of the conveyor belt to the other? Round your answer to the nearest foot. If the belt moves at 75 ft/min, how long, to the nearest tenth of a minute, does it take the supplies to move to the second floor? (1 point) 47 ft; 38 min 31 ft; 0.4 min 38 ft; 23.3 min 16 ft; 1.1 min

    • one year ago
  104. jim_thompson5910
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    first draw out a picture

    • one year ago
  105. jim_thompson5910
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    |dw:1363124336238:dw|

    • one year ago
  106. jim_thompson5910
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    you want to find x

    • one year ago
  107. jim_thompson5910
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    because you want to find the length of the belt

    • one year ago
  108. jim_thompson5910
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    so sin(60) = 27/x x*sin(60) = 27 x = 27/sin(60) x = ??

    • one year ago
  109. Emily778
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    31.17

    • one year ago
  110. jim_thompson5910
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    so it's 31 (since you round to the nearest foot)

    • one year ago
  111. jim_thompson5910
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    you don't need to do the second part since there's only one answer with 31 ft

    • one year ago
  112. Emily778
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    @jim_thompson5910 Find the missing value to the nearest hundredth. tan= 38 88.49 61.25 65.25 44.25

    • one year ago
  113. jim_thompson5910
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    tan(x) = 38 x = arctan(38) x = ???

    • one year ago
  114. Emily778
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    I get 0.78?

    • one year ago
  115. jim_thompson5910
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    not the tangent of 38 the arctangent of 38

    • one year ago
  116. Emily778
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    woah.

    • one year ago
  117. Emily778
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    Find the missing value to the nearest hundredth. Sin= 8/32 75.52 14.04 77.76 14.48

    • one year ago
  118. Emily778
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    how do I find that?

    • one year ago
  119. jim_thompson5910
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    yeah I used google as a calculator

    • one year ago
  120. jim_thompson5910
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    type "arcsin(8/32) in degrees" without quotes into google

    • one year ago
  121. jim_thompson5910
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    and it will act like a calculator and give you the result

    • one year ago
  122. jim_thompson5910
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    if you do that, you will get this http://www.google.com/search?hl=&q=arcsin%288%2F32%29+in+degrees&sourceid=navclient-ff&rlz=1B3GGLL_enUS420US420&ie=UTF-8

    • one year ago
  123. Emily778
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    Write the tangent ratios for Y and Z. The triangle is not drawn to scale.

    • one year ago
  124. Emily778
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    @jim_thompson5910

    • one year ago
  125. jim_thompson5910
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    remember that tan = opposite/adjacent

    • one year ago
  126. jim_thompson5910
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    so in the case of angle Y 6 is the opposite side 7 is the adjacent side tan(Y) = opp/adj tan(Y) = 6/7

    • one year ago
  127. Emily778
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    And tan z =7/6 then?

    • one year ago
  128. jim_thompson5910
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    yes good, tan(Z) = 7/6

    • one year ago
  129. Emily778
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    2. Write the ratios for sin A and cos A. The triangle is not drawn to scale. (1 point)

    • one year ago
  130. Emily778
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    @jim_thompson5910

    • one year ago
  131. jim_thompson5910
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    keep in mind that sin = opp/hyp cos = adj/hyp

    • one year ago
  132. Emily778
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    opp= opposite? eh, can you show me?

    • one year ago
  133. jim_thompson5910
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    correct, adj = adjacent

    • one year ago
  134. jim_thompson5910
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    in terms of angle A, which is the opposite side? adjacent side?

    • one year ago
  135. Emily778
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    65?

    • one year ago
  136. jim_thompson5910
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    that would be the hypotenuse, which is the longest side

    • one year ago
  137. Emily778
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    oh, so it's 16

    • one year ago
  138. jim_thompson5910
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    16 is the adjacent side since it's part of angle A

    • one year ago
  139. Emily778
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    can you just show me how to do it?

    • one year ago
  140. jim_thompson5910
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    opp = 63 adj = 16 hyp = 65

    • one year ago
  141. jim_thompson5910
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    sin(A) = opp/hyp sin(A) = ?? cos(A) = adj/hyp cos(A) = ??

    • one year ago
  142. Emily778
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    i dont get it

    • one year ago
  143. jim_thompson5910
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    just plug in the given values, that's all you do really

    • one year ago
  144. Emily778
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    but i don't now which is opposite and adjacent and hypotenuse

    • one year ago
  145. jim_thompson5910
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    I just gave you those values opp = 63 adj = 16 hyp = 65

    • one year ago
  146. Emily778
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    Find the value of x. Round to the nearest tenth. The triangle is not drawn to scale. (1 point) 11.9 10.3 11.7 10.8

    • one year ago
  147. jim_thompson5910
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    cos(20) = x/11 solve for x

    • one year ago
  148. Emily778
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    i GOT 0.084. O- O

    • one year ago
  149. Emily778
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    Oops

    • one year ago
  150. jim_thompson5910
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    you would do x = 11*cos(20) x = ??

    • one year ago
  151. Emily778
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    10.33

    • one year ago
  152. jim_thompson5910
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    yep, but it's pretty late to be doing math (I'm about to log off)

    • one year ago
  153. Emily778
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    :D

    • one year ago
  154. Emily778
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    Oh, okay :p

    • one year ago
  155. jim_thompson5910
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    we can do it tomorrow if you want

    • one year ago
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