Emily778 Group Title Find the length of the missing side. Leave your answer in simplest radical form. The triangle is not drawn to scale. one year ago one year ago

1. Emily778

2. jim_thompson5910

a^2 + b^2 = c^2 5^2 + 13^2 = c^2 solve for c

3. Emily778

159^2?

4. jim_thompson5910

5^2 + 13^2 = c^2 25 + 169 = c^2 194 = c^2 c^2 = 194 c = ???

5. Emily778

I don't know.

6. jim_thompson5910

what undoes a square?

7. Emily778

is it sqrt 194?

8. jim_thompson5910

you got it

9. jim_thompson5910

the missing side is $\Large \sqrt{194}$ units

10. Emily778

11. jim_thompson5910

yes

12. Emily778

A triangle has sides of lengths 27, 79, and 84. Is it a right triangle? Explain. (1 point) yes; 272 + 792 842 no; 272 + 792 = 842 no; 272 + 792 842 yes; 272 + 792 = 842

13. jim_thompson5910

what is 27^2 + 79^2

14. Emily778

6,970

15. jim_thompson5910

what is 84^2

16. Emily778

7,056

17. jim_thompson5910

so 6970 is not equal to 7056 which means 27^2 + 79^2 is not equal to 84^2

18. jim_thompson5910

so that proves you don't have a right triangle

19. Emily778

so, it's b?

20. jim_thompson5910

what does C say

21. jim_thompson5910

it seems like a symbol is missing

22. Emily778

It's = sign with a line through it.

23. jim_thompson5910

like this |dw:1362982562480:dw| ??

24. jim_thompson5910

if so, then it's C

25. Emily778

yeah, it does look like that. What's that mean?

26. jim_thompson5910

it means "not equal"

27. Emily778

oh, so it is C

28. jim_thompson5910

it's kinda like a "no smoking" sign where it's crossed out

29. jim_thompson5910

yes

30. Emily778

A triangle has side lengths of 12 cm, 35 cm, and 37 cm. Classify it as acute, obtuse, or right. (1 point) acute obtuse right

31. jim_thompson5910

12^2 + 35^2 is what

32. Emily778

1,369

33. jim_thompson5910

37^2 is _____

34. Emily778

1,369

35. jim_thompson5910

the two are the same, so 12^2 + 35^2 = 37^2

36. jim_thompson5910

which means that you have a right triangle

37. Emily778

one more? :)

38. jim_thompson5910

go for it

39. Emily778

oops. I don't know how I typed that. That was weird. :/

40. Emily778

. Find the value of the variable. If your answer is not an integer, leave it in simplest radical form. The triangle is not drawn to scale. (1 point) Find the value of the variable. If your answer is not an integer, leave it in simplest radical form. The triangle is not drawn to scale.

41. Emily778

woah..Didn't mean to say that twice

42. jim_thompson5910

that's ok, yeah OS has its glitches from time to time

43. jim_thompson5910

so you basically want to find x right?

44. Emily778

I don't know. These are the possible answers.

45. Emily778

46. Emily778

47. jim_thompson5910

if so, then a^2 + b^2 = c^2 x^2 + x^2 = 7^2 2x^2 = 49 x^2 = 49/2 x = sqrt(49/2) x = sqrt(49)/sqrt(2) x = 7/sqrt(2) x = 7sqrt(2)/sqrt(2)*sqrt(2) x = 7sqrt(2)/2 So |dw:1362983836880:dw|

48. Emily778

49. jim_thompson5910
50. Emily778

okay, thanks :)

51. jim_thompson5910

you're welcome

52. Emily778

The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter.

53. Emily778

DO YOU KNOW THIS ONE? D:

54. jim_thompson5910

did you put on your THINKING CAPS ? lol jk

55. jim_thompson5910

we know this much |dw:1362983975619:dw|

56. jim_thompson5910

that's what we're given

57. jim_thompson5910

the hypotenuse is twice as long as the shorter leg, so the hypotenuse is 2*3 = 6

58. jim_thompson5910

|dw:1362984054235:dw|

59. jim_thompson5910

the longer leg is sqrt(3) times longer than the shorter leg so the longer leg is 3*sqrt(3)

60. jim_thompson5910

|dw:1362984092454:dw|

61. jim_thompson5910

Now add up all the sides $\Large 3+6+3\sqrt{3}$ $\Large 9+3\sqrt{3}$

62. Emily778

14.19

63. jim_thompson5910

that's the approximate perimeter, good

64. Emily778

that's not one of the answers

65. jim_thompson5910

66. Emily778

x= 13, y=39 sqrt 3 x= 13 sqrt 3, y=39 x=39,y= 13 sqrt 3 x=39 sqrt 3, y=13

67. jim_thompson5910

something seems missing

68. jim_thompson5910

it wanted the perimeter, not x and y whatever those values refer to

69. Emily778

x and y are the perimeters.

70. jim_thompson5910

a triangle only has one perimeter

71. jim_thompson5910

is there a way you can post a screenshot of this problem?

72. Emily778

Well, it's like an upside down triangle.

73. Emily778

so, I guess the base is Y

74. jim_thompson5910

is a screenshot not possible?

75. Emily778

76. jim_thompson5910

this looks like a totally different problem what happened with the one "The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter."

77. jim_thompson5910

odd

78. jim_thompson5910

so this is the real problem? the other problem wasn't the one you wanted to do?

79. Emily778

Oh my gosh. I'm so tired. I gave you another problem..

80. jim_thompson5910

i see, we can do this tomorrow if you want

81. Emily778

@jim_thompson5910

82. Emily778

The length of the small leg of a 30°-60°-90° triangle is 3. Find the perimeter. (1 point) 9/2 + 3/2 sqrt 3 3/2 +9/2 sqrt 3 3+9 sqrt 3 9+3 sqrt 3

83. Emily778

@jim_thompson5910

84. jim_thompson5910

we did this one already |dw:1363121467711:dw|

85. jim_thompson5910

3+6 + 3*sqrt(3) 9 + 3*sqrt(3)

86. Emily778

I got 14.19

87. jim_thompson5910

Leave it in radical form So it would be $\Large 9 + 3\sqrt{3}$

88. Emily778

so, it's d?

89. jim_thompson5910

yes

90. Emily778

Thankyou. can you help me with more?

91. Emily778

Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form. This triangle is not drawn to scale. (1 point) x = 13, y = 39 sqrt 3 x = 13 sqrt 3, y = 39 x = 39, y = 13 sqrt 3 x = 39 sqrt 3, y = 13

92. Emily778

93. Emily778

@jim_thompson5910

94. jim_thompson5910

we did this one too

95. jim_thompson5910

hmm

96. jim_thompson5910

do you remember doing this?

97. Emily778

we didn't. I accidentally mixed this one with the other one, though

98. jim_thompson5910

alright, the shorter leg is half of the hypotenuse so the shorter leg is 13*sqrt(3) this means y = 13*sqrt(3)

99. Emily778

okay

100. jim_thompson5910

the longer leg is sqrt(3) times longer than the shorter leg, so... x = y*sqrt(3) x = 13*sqrt(3)*sqrt(3) x = 13*3 x = 39

101. Emily778

what's y=?

102. jim_thompson5910

$\Large y = 13\sqrt{3}$

103. Emily778

Do you get this? A conveyor belt carries supplies from the first floor to the second floor, which is 27 feet higher. The belt makes a 60° angle with the ground. How far do the supplies travel from one end of the conveyor belt to the other? Round your answer to the nearest foot. If the belt moves at 75 ft/min, how long, to the nearest tenth of a minute, does it take the supplies to move to the second floor? (1 point) 47 ft; 38 min 31 ft; 0.4 min 38 ft; 23.3 min 16 ft; 1.1 min

104. jim_thompson5910

first draw out a picture

105. jim_thompson5910

|dw:1363124336238:dw|

106. jim_thompson5910

you want to find x

107. jim_thompson5910

because you want to find the length of the belt

108. jim_thompson5910

so sin(60) = 27/x x*sin(60) = 27 x = 27/sin(60) x = ??

109. Emily778

31.17

110. jim_thompson5910

so it's 31 (since you round to the nearest foot)

111. jim_thompson5910

you don't need to do the second part since there's only one answer with 31 ft

112. Emily778

@jim_thompson5910 Find the missing value to the nearest hundredth. tan= 38 88.49 61.25 65.25 44.25

113. jim_thompson5910

tan(x) = 38 x = arctan(38) x = ???

114. Emily778

I get 0.78?

115. jim_thompson5910

not the tangent of 38 the arctangent of 38

116. jim_thompson5910
117. Emily778

woah.

118. Emily778

Find the missing value to the nearest hundredth. Sin= 8/32 75.52 14.04 77.76 14.48

119. Emily778

how do I find that?

120. jim_thompson5910

yeah I used google as a calculator

121. jim_thompson5910

type "arcsin(8/32) in degrees" without quotes into google

122. jim_thompson5910

and it will act like a calculator and give you the result

123. jim_thompson5910

if you do that, you will get this http://www.google.com/search?hl=&q=arcsin%288%2F32%29+in+degrees&sourceid=navclient-ff&rlz=1B3GGLL_enUS420US420&ie=UTF-8

124. Emily778

Write the tangent ratios for Y and Z. The triangle is not drawn to scale.

125. Emily778

@jim_thompson5910

126. jim_thompson5910

127. jim_thompson5910

so in the case of angle Y 6 is the opposite side 7 is the adjacent side tan(Y) = opp/adj tan(Y) = 6/7

128. Emily778

And tan z =7/6 then?

129. jim_thompson5910

yes good, tan(Z) = 7/6

130. Emily778

2. Write the ratios for sin A and cos A. The triangle is not drawn to scale. (1 point)

131. Emily778

@jim_thompson5910

132. jim_thompson5910

keep in mind that sin = opp/hyp cos = adj/hyp

133. Emily778

opp= opposite? eh, can you show me?

134. jim_thompson5910

135. jim_thompson5910

in terms of angle A, which is the opposite side? adjacent side?

136. Emily778

65?

137. jim_thompson5910

that would be the hypotenuse, which is the longest side

138. Emily778

oh, so it's 16

139. jim_thompson5910

16 is the adjacent side since it's part of angle A

140. Emily778

can you just show me how to do it?

141. jim_thompson5910

opp = 63 adj = 16 hyp = 65

142. jim_thompson5910

sin(A) = opp/hyp sin(A) = ?? cos(A) = adj/hyp cos(A) = ??

143. Emily778

i dont get it

144. jim_thompson5910

just plug in the given values, that's all you do really

145. Emily778

but i don't now which is opposite and adjacent and hypotenuse

146. jim_thompson5910

I just gave you those values opp = 63 adj = 16 hyp = 65

147. Emily778

Find the value of x. Round to the nearest tenth. The triangle is not drawn to scale. (1 point) 11.9 10.3 11.7 10.8

148. jim_thompson5910

cos(20) = x/11 solve for x

149. Emily778

i GOT 0.084. O- O

150. Emily778

Oops

151. jim_thompson5910

you would do x = 11*cos(20) x = ??

152. Emily778

10.33

153. jim_thompson5910

yep, but it's pretty late to be doing math (I'm about to log off)

154. Emily778

:D

155. Emily778

Oh, okay :p

156. jim_thompson5910

we can do it tomorrow if you want