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LordHades
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There are 8 electrical engineers and 12 computer engineers who are doing a group project. We need to divide them into 4 groups of 5 so that each group contains exactly 2 electrical engineers and 3 computer engineers. How many ways can this be done?
 one year ago
 one year ago
LordHades Group Title
There are 8 electrical engineers and 12 computer engineers who are doing a group project. We need to divide them into 4 groups of 5 so that each group contains exactly 2 electrical engineers and 3 computer engineers. How many ways can this be done?
 one year ago
 one year ago

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wio Group TitleBest ResponseYou've already chosen the best response.1
You want to split up the problem into simple, easily counted tasks.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
I'd first assign each group their electrical engineers, then assign them their computer engineers.
 one year ago

LordHades Group TitleBest ResponseYou've already chosen the best response.0
so 8! / 6! + 12! / 9!
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
These are sequential tasks, so you multiply their counts...
 one year ago

LordHades Group TitleBest ResponseYou've already chosen the best response.0
i don't understand how you got to 8 ways.
 one year ago

Zoodude Group TitleBest ResponseYou've already chosen the best response.0
495 is the answer I just checked on the calculator
 one year ago

LordHades Group TitleBest ResponseYou've already chosen the best response.0
Yes, but how exactly do you get that?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
For assigning electrical engineers, I would try: \[ \binom{8}{2}\cdot \binom{6}{2}\cdot \binom{4}{2}\cdot \binom{2}{2} \]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
For assigning computer engineers, I would try: \[ \binom{12}{3}\cdot \binom{9}{3}\cdot \binom{6}{3}\cdot \binom{3}{3} \]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
The total count would be the product of these two.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Do you understand it?
 one year ago

LordHades Group TitleBest ResponseYou've already chosen the best response.0
Most of it. Why would you multiply rather than add?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
You add when you have an option of doing either task. You multiply when you have two do both tasks.
 one year ago

LordHades Group TitleBest ResponseYou've already chosen the best response.0
That would make sense since in this question it's an "and".
 one year ago
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