Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

LordHades

  • 2 years ago

There are 8 electrical engineers and 12 computer engineers who are doing a group project. We need to divide them into 4 groups of 5 so that each group contains exactly 2 electrical engineers and 3 computer engineers. How many ways can this be done?

  • This Question is Closed
  1. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You want to split up the problem into simple, easily counted tasks.

  2. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'd first assign each group their electrical engineers, then assign them their computer engineers.

  3. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so 8! / 6! + 12! / 9!

  4. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    These are sequential tasks, so you multiply their counts...

  5. Zoodude
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    8 ways

  6. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't understand how you got to 8 ways.

  7. Zoodude
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    495 is the answer I just checked on the calculator

  8. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, but how exactly do you get that?

  9. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    For assigning electrical engineers, I would try: \[ \binom{8}{2}\cdot \binom{6}{2}\cdot \binom{4}{2}\cdot \binom{2}{2} \]

  10. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    For assigning computer engineers, I would try: \[ \binom{12}{3}\cdot \binom{9}{3}\cdot \binom{6}{3}\cdot \binom{3}{3} \]

  11. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The total count would be the product of these two.

  12. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks.

  13. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you understand it?

  14. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Most of it. Why would you multiply rather than add?

  15. wio
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You add when you have an option of doing either task. You multiply when you have two do both tasks.

  16. LordHades
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That would make sense since in this question it's an "and".

  17. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.